LeetCode--181. Employees Earning More Than Their Managers

找出薪资高于上级的员工

最新推荐文章于 2021-10-23 05:24:25 发布

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最新推荐文章于 2021-10-23 05:24:25 发布

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分类专栏： leetcode 数据库文章标签： leetcode mysql

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本文介绍了一种使用SQL查询的方法来找出那些薪资高于其直接上级的员工。通过使用内连接(join)或在where子句中指定条件，可以有效地从包含员工及其上级信息的数据表中筛选出所需的数据。

Problem:

The Employee table holds all employees including their managers.
Every employee has an Id, and there is also a column for the managerId.

+----+-------+--------+-----------+
| Id | Name  | Salary | ManagerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | NULL      |
| 4  | Max   | 90000  | NULL      |
+----+-------+--------+-----------+

Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.

+----------+
| Employee |
+----------+
| Joe      |
+----------+

Analysis:
这个题计较简单，主要用到内连接join的思想。
Answer:

#用join内连接
# Write your MySQL query statement below
select e1.name from Employee e1
join Employee e2 on e1.ManagerId=e2.Id
where e1.Salary>e2.Salary;

或者

#用where
# Write your MySQL query statement below
select e1.name from Employee e1,Employee e2 
where e1.ManagerId=e2.Id
and e1.Salary>e2.Salary;