应用栈先进后出的原则完成十进制转换成二进制
代码:
#include <stdio.h>
#include <malloc.h>
typedef struct node{
int data;
struct node *next;
}Stack;
void StackInit(Stack *top)
{
top->next=NULL;
}
int Push(Stack *p,int x)
{
Stack *a;
a=(Stack *)malloc(sizeof(Stack));
if(p==NULL)
return 0;
a->data=x;
a->next=p->next;
p->next=a;
return 1;
}
int IsEmpty(Stack *top) //判断栈是否为空
{
if(top->next==NULL)
return 1;
return 0;
}
int Pop(Stack *top,int *x)
{
Stack *p;
if(IsEmpty(top))
return 0;
p=top->next;
*x=p->data;
top->next=p->next;
free(p);
return 1;
}
int main()
{
int x;
Stack *top;
top=(Stack *)malloc(sizeof(Stack));
StackInit (top); //栈的初始化
printf("decimal:\n"); //输入十进制数
scanf("%d",&x);
while(x)
{
Push(top,x%2); //进栈
x=x/2;
}
printf("binary:\n");
while(Pop(top,&x)) //出栈
{
printf("%d",x); //输出二进制数
}
printf("\n");
return 0;
}