杭电HDOJ
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杭电HDOJ 1042 解题报告
N!Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 41380 Accepted Submission(s): 11478Problem DescriptionGiven an integer N(0原创 2013-04-22 20:41:28 · 604 阅读 · 0 评论 -
ACM STEP 1.1.3A+B for Input-Output Practice (III)
#include using namespace std;int main(int argc, const char * argv[]){ int a,b; while(cin >>a>>b) { if(a==0&&b==0) break; cout <<a+b<<endl; } return 0;}原创 2013-10-11 19:50:09 · 498 阅读 · 0 评论 -
ACM STEP 1.1.6 A+B for Input-Output Practice (VI)
#include using namespace std;int main(int argc, const char * argv[]){ int a,sum,n; while((cin >>n)&&n!=0) { sum=0; while(n--) { cin >>a; sum+=a;原创 2013-10-11 19:53:18 · 591 阅读 · 0 评论 -
ACM STEP 1.1.7 A+B for Input-Output Practice (VII)
#include using namespace std;int main(int argc, const char * argv[]){ int a,b; while(cin >>a>>b) { cout <<a+b<<endl<<endl; } return 0;}原创 2013-10-11 19:55:39 · 545 阅读 · 0 评论 -
ACM STEP 1.1.8 A+B for Input-Output Practice (VIII)
#include using namespace std;int main(int argc, const char * argv[]){ int n,k,sum,f=0,a; cin >>n; while(n--) { if(f) { cout <<endl; } cin原创 2013-10-11 19:56:29 · 587 阅读 · 0 评论 -
ACM STEP 1.2.1 Climbing Worm
Climbing WormTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2609 Accepted Submission(s): 1548 Problem Descriptio原创 2013-10-11 19:59:03 · 618 阅读 · 0 评论 -
ACM STEP 1.2.2 Financial Management
Financial ManagementTime Limit: 400/200 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2867 Accepted Submission(s): 1381 Problem Descr原创 2013-10-11 20:00:22 · 642 阅读 · 0 评论 -
ACM STEP 1.2.5 GPA
GPATime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2648 Accepted Submission(s): 1097 Problem DescriptionEach原创 2013-10-11 20:04:15 · 803 阅读 · 0 评论 -
杭电ACM Step 纪念
杭电ACM STEP。转C++的时候发现杭电OJ上居然有一个ACM STEP，饶有兴趣的去写了写，虽然我的代码有点水，不过还是很希望各位同志能给我点意见。原创 2013-10-11 19:41:31 · 843 阅读 · 0 评论 -
ACM STEP 1.1.4 A+B for Input-Output Practice (IV)
#include using namespace std;int main(int argc, const char * argv[]){ int a,sum,n; while((cin >>n)&&n!=0) { sum=0; while(n--) { cin >>a; sum+=a;原创 2013-10-11 19:51:13 · 569 阅读 · 0 评论 -
ACM STEP 1.2.3 Nasty Hacks
Nasty HacksTime Limit: 3000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2161 Accepted Submission(s): 1359 Problem Description原创 2013-10-11 20:01:37 · 664 阅读 · 0 评论 -
ACM STEP 1.2.4 find your present (2)
find your present (2)Time Limit: 1000/2000 MS (Java/Others) Memory Limit: 32768/1024 K (Java/Others)Total Submission(s): 4216 Accepted Submission(s): 1251 Problem Des原创 2013-10-11 20:02:51 · 684 阅读 · 0 评论 -
ACM STEP 1.1.5A+B for Input-Output Practice (V)
#include using namespace std;int main(int argc, const char * argv[]){ int a,b,sum,n; cin >>n; sum=0; while(n--) { cin >>b; while(b--) { cin >>a;原创 2013-10-11 19:52:11 · 595 阅读 · 0 评论 -
ACM STEP 1.1.2 A+B for Input-Output Practice (II)
#include using namespace std;int main(int argc, const char * argv[]){ int a,b,n; cin >>n; while(n--) { cin >>a>>b; cout <<a+b<<endl; } return 0;}原创 2013-10-11 19:48:51 · 468 阅读 · 0 评论 -
ACM STEP1.1.1
#include using namespace std;int main(int argc, const char * argv[]){ int a,b; while(cin >>a>>b) { cout <<a+b<<endl; } return 0;}原创 2013-10-11 19:47:12 · 548 阅读 · 0 评论 -
杭电HDOJ 1040 解题报告
As Easy As A+BTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 27708 Accepted Submission(s): 11774Problem DescriptionThese day原创 2013-04-22 20:50:04 · 823 阅读 · 0 评论 -
杭电HDOJ 1159 解题报告
Common SubsequenceTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 15869 Accepted Submission(s): 6625Problem DescriptionA subs原创 2013-04-20 12:53:57 · 866 阅读 · 0 评论 -
杭电HDOJ 1000 解题报告
A + B ProblemTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 302935 Accepted Submission(s): 87561Problem DescriptionCalculate原创 2013-04-20 12:57:11 · 583 阅读 · 0 评论 -
杭电HDOJ1024 解题报告
Max Sum Plus PlusTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11955 Accepted Submission(s): 3944Problem DescriptionNow I t原创 2013-04-19 19:25:46 · 843 阅读 · 0 评论 -
杭电HDOJ 2084 解题报告
数塔Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 14364 Accepted Submission(s): 8549Problem Description在讲述DP算法的时候，一个经典的例子就是数塔原创 2013-04-20 12:12:11 · 607 阅读 · 0 评论 -
杭电HDOJ 1001 解题报告
Sum ProblemTime Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 209891 Accepted Submission(s): 50826Problem DescriptionHey, welcome原创 2013-04-20 13:13:57 · 630 阅读 · 0 评论 -
杭电HDOJ 1003 解题报告
Max SumTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 103698 Accepted Submission(s): 23844Problem DescriptionGiven a sequenc原创 2013-04-21 22:44:22 · 651 阅读 · 0 评论 -
杭电HDOJ 1002 解题报告
A + B Problem IITime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 154489 Accepted Submission(s): 29230Problem DescriptionI have原创 2013-04-21 22:20:40 · 800 阅读 · 0 评论 -
杭电HDOJ 1160 解题报告
FatMouse's SpeedTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6632 Accepted Submission(s): 2898Special JudgeProblem Description原创 2013-04-21 22:53:28 · 651 阅读 · 0 评论 -
杭电HDOJ 1061 解题报告
Rightmost DigitTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 24000 Accepted Submission(s): 9155Problem DescriptionGiven a p原创 2013-05-03 15:21:08 · 656 阅读 · 0 评论 -
杭电HDOJ 1097 解题报告
A hard puzzleTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 23044 Accepted Submission(s): 8089Problem Descriptionlcy gives a原创 2013-05-03 16:14:20 · 784 阅读 · 0 评论 -
杭电HDOJ 1060 解题思路
Leftmost DigitTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 10180 Accepted Submission(s): 3867Problem DescriptionGiven a po原创 2013-05-03 15:32:08 · 595 阅读 · 0 评论 -
ACM STEP 1.2.7 Lowest Bit
Lowest BitTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1787 Accepted Submission(s): 1248 Problem Description原创 2013-10-11 20:05:27 · 1117 阅读 · 1 评论