题目:
59. Spiral Matrix II
Given a positive integer n, generate a square matrix filled with elements from 1 to n^2 in spiral order.
Example:
Input: 3
Output:
[
[ 1, 2, 3 ],
[ 8, 9, 4 ],
[ 7, 6, 5 ]
]
思路:
按层处理,每层处理一圈
代码:
class Solution {
public:
vector<vector<int>> generateMatrix(int n) {
vector<vector<int> > vec(n, vector<int>(n, 0));
int row = n-1;
int col = n-1;
int x = 0;
int y = 0;
int value = 1;
while(true){
if(x > col)return vec;
else if(x == col){
vec[x][x] = value;
return vec;
}
for(int i = x; i <= col; ++i)
vec[y][i] = value++;
for(int i = y+1; i <= row; ++i)
vec[i][col] = value++;
for(int i = col-1; i >= x; --i)
vec[row][i] = value++;
for(int i = row-1; i > y; --i)
vec[i][x] = value++;
++x;++y;
--row;--col;
}
return vec;
}
};
结果:

一遍过,干净易懂,nice~~