作者:小代码
时间:2013年7月22日21:47:29
IDE:CodeBlocks
题目:
-
题目描述:
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每天第一个到机房的人要把门打开,最后一个离开的人要把门关好。现有一堆杂乱的机房签到、签离记录,请根据记录找出当天开门和关门的人。
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输入:
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测试输入的第一行给出记录的总天数N ( N> 0 ),下面列出了N天的记录。
每天的记录在第一行给出记录的条目数M (M > 0 ),下面是M行,每行的格式为
证件号码 签到时间 签离时间
其中时间按“小时:分钟:秒钟”(各占2位)给出,证件号码是长度不超过15的字符串。
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输出:
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对每一天的记录输出1行,即当天开门和关门人的证件号码,中间用1空格分隔。
注意:在裁判的标准测试输入中,所有记录保证完整,每个人的签到时间在签离时间之前,且没有多人同时签到或者签离的情况。
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样例输入:
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3 1 ME3021112225321 00:00:00 23:59:59 2 EE301218 08:05:35 20:56:35 MA301134 12:35:45 21:40:42 3 CS301111 15:30:28 17:00:10 SC3021234 08:00:00 11:25:25 CS301133 21:45:00 21:58:40
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样例输出:
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ME3021112225321 ME3021112225321 EE301218 MA301134 SC3021234 CS301133
C语言超时版:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main( void )
{
void MyScanf( char *number, char *openTime, char *closeTime );//接收记录
char *openTime = (char*)malloc(sizeof(char)*9);
char *closeTime = (char*)malloc(sizeof(char)*9);
char *openTimeTemp = (char*)malloc(sizeof(char)*9);
char *closeTimeTemp = (char*)malloc(sizeof(char)*9);
char *open = (char*)malloc(sizeof(char)*16);
char *close = (char*)malloc(sizeof(char)*16);
char *number = (char*)malloc(sizeof(char)*16);
int N;
int num;
int i = 0;
int j = 0;
scanf("%d",&N);
for( i = 0; i < N; i++ )
{
scanf("%d",&num);
getchar();
for( j = 0; j < num; j++ )
{
if( 0 == j )//接收第一个
{
MyScanf( number, openTime, closeTime );
open = strcpy( open, number );
close = strcpy( close, number );
}
else
{
MyScanf( number, openTimeTemp, closeTimeTemp );//接收其他
if( 0 < strcmp(openTime,openTimeTemp))//比较开门时间
{
open = strcpy( open, number );
openTime = strcpy( openTime, openTimeTemp );
}
if( 0 > strcmp( closeTime, closeTimeTemp ))//比较关门时间
{
close = strcpy( close, number );
closeTime = strcpy( closeTime, closeTimeTemp );
}
}
}
printf("%s %s\n",open,close);//输出结果
}
return 0;
}
//接收记录
void MyScanf( char *number, char *openTime, char *closeTime )
{
char in;
int i = 0;
int j = 0;
int k = 0;
int t = 0;
while( '\n' != ( in = getchar() ) )
{
if( ' ' == in )//遇到空格就接收下一个字符串
{
i++;
continue;
}
switch ( i )
{
case 0:
*( number + j ) = in;
j++;
break;
case 1:
*( openTime + k ) = in;
k++;
break;
case 2:
*( closeTime + t ) = in;
t++;
break;
default:
break;
}
}
*( number + j ) = '\0';
*( openTime + k ) = '\0';
*( closeTime + t ) = '\0';
}
C语言第一次修改通过版:
时间:2013年7月22日23:32:54
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
int main( void )
{
int N;
int num;
char *open = (char*)malloc(sizeof(char)*16);
char *close = (char*)malloc(sizeof(char)*16);
char*number = (char*)malloc(sizeof(char)*16);
char *openTime = (char*)malloc(sizeof(char)*9);
char *closeTime = (char*)malloc(sizeof(char)*9);
char *openTimeTemp = (char*)malloc(sizeof(char)*9);
char *closeTimeTemp = (char*)malloc(sizeof(char)*9);
int i = 0;
int j = 0;
scanf("%d",&N);
for( i = 0; i < N; i++ )
{
scanf("%d",&num);
for( j = 0; j < num; j++ )
{
if( 0 == j )
{
scanf("%s",number);
scanf("%s",openTime);
scanf("%s",closeTime);
strcpy( open, number );
strcpy( close, open );
//printf("-----测试----open = **%s**\tclose = **%s**\topenTime = **%s**\tcloseTime = **%s**\n",open,close,openTime,closeTime);
}
else
{
scanf("%s",number);
scanf("%s",openTimeTemp);
scanf("%s",closeTimeTemp);
if( 0 < strcmp(openTime,openTimeTemp))//比较开门时间
{
strcpy( open, number );
strcpy( openTime, openTimeTemp );
}
if( 0 > strcmp( closeTime, closeTimeTemp ))//比较关门时间
{
strcpy( close, number );
strcpy( closeTime, closeTimeTemp );
}
//printf("-----测试----open = **%s**\tclose = **%s**\topenTime = **%s**\tcloseTime = **%s**\n",open,close,openTime,closeTime);
}
}
printf("%s %s\n",open,close);
}
return 0;
}