Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note: The solution set must not contain duplicate triplets.
For example, given array S = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
vector<vector<int>> threeSum(vector<int>& nums) {
vector<vector<int>> res;
if (nums.size() < 3)return res;
sort(nums.begin(), nums.end());
for (int i = 0; i < nums.size() - 2; i++){
if (i > 0 && nums[i] == nums[i - 1]){
continue;
}
int left = i + 1, right = nums.size() - 1;
int prev = nums[i];
while (left < right){
if (prev + nums[left] + nums[right] > 0){
right--;
while (nums[right] == nums[right + 1])right--;
}
else if (prev + nums[left] + nums[right] < 0){
left++;
while (nums[left] == nums[left - 1])left++;
}
else{
res.push_back({ prev, nums[left], nums[right] });
left++, right--;
while (nums[left] == nums[left - 1] && nums[right] == nums[right + 1])left++, right--;
}
}
}
return res;
}