Hive级联求和_hive group by的时候如何再叠加一个整体求和-优快云博客

本文链接：https://blog.youkuaiyun.com/jiayi_yao/article/details/124596339

该博客介绍了如何在Hive中通过SQL查询对用户每个月的工资进行分组统计和月累计求和。首先，对原始数据进行分组求和得到每个用户每月的总工资；然后，通过自身连接获取每个用户工资的月累计值；最后，通过分组和聚合操作得到月累计工资的结果。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

create table t_salary_detail(username string,month string,salary int)
row format delimited fields terminated by ',';

load data local inpath '/root/hivedata/t_salary_detail.dat' into table t_salary_detail;

A,2015-01,5
A,2015-01,15
B,2015-01,5
A,2015-01,8
B,2015-01,25
A,2015-01,5
A,2015-02,4
A,2015-02,6
B,2015-02,10
B,2015-02,5
A,2015-03,7
A,2015-03,9
B,2015-03,11
B,2015-03,6

需求：统计每个用户每个月获得多少小费？
分组维度： username month

1、第一步，先求每个用户的月总金额
select username,month,sum(salary) as salary from t_salary_detail group by username,month;

+-----------+----------+---------+-
| username | month | salary |
+-----------+----------+---------+-
| A | 2015-01 | 33 |
| A | 2015-02 | 10 |
| A | 2015-03 | 16 |
| B | 2015-01 | 33 |
| B | 2015-02 | 15 |
| B | 2015-03 | 17 |
+-----------+----------+---------+--+

2、第二步，将月总金额表自己连接自己
select A.*,B.* FROM
(select username,month,sum(salary) as salary from t_salary_detail group by username,month) A
inner join
(select username,month,sum(salary) as salary from t_salary_detail group by username,month) B
on
A.username=B.username
where B.month <= A.month
+-------------+----------+-----------+-------------+----------+-----------+--+
| a.username | a.month | a.salary | b.username | b.month | b.salary |
+-------------+----------+-----------+-------------+----------+-----------+--+
| A | 2015-01 | 33 | A | 2015-01 | 33 |
| A | 2015-02 | 10 | A | 2015-01 | 33 |
| A | 2015-02 | 10 | A | 2015-02 | 10 |
| A | 2015-03 | 16 | A | 2015-01 | 33 |
| A | 2015-03 | 16 | A | 2015-02 | 10 |
| A | 2015-03 | 16 | A | 2015-03 | 16 |
| B | 2015-01 | 30 | B | 2015-01 | 30 |
| B | 2015-02 | 15 | B | 2015-01 | 30 |
| B | 2015-02 | 15 | B | 2015-02 | 15 |
| B | 2015-03 | 17 | B | 2015-01 | 30 |
| B | 2015-03 | 17 | B | 2015-02 | 15 |
| B | 2015-03 | 17 | B | 2015-03 | 17 |
+-------------+----------+-----------+-------------+----------+-----------+--+

不加where B.month <= A.month的执行结果：

3、第三步，从上一步的结果中
进行分组查询，分组的字段是a.username a.month
求月累计值：将b.month <= a.month的所有b.salary求和即可
select A.username,A.month,max(A.salary) as salary,sum(B.salary) as accumulate
from
(select username,month,sum(salary) as salary from t_salary_detail group by username,month) A
inner join
(select username,month,sum(salary) as salary from t_salary_detail group by username,month) B
on
A.username=B.username
where B.month <= A.month
group by A.username,A.month
order by A.username,A.month;

+-------------+----------+---------+-------------+--+
| a.username | a.month | salary | accumulate |
+-------------+----------+---------+-------------+--+
| A | 2015-01 | 33 | 33 |
| A | 2015-02 | 10 | 43 |
| A | 2015-03 | 16 | 59 |
| B | 2015-01 | 30 | 30 |
| B | 2015-02 | 15 | 45 |
| B | 2015-03 | 17 | 62 |
+-------------+----------+---------+-------------+--+