uva_401

这道题较为简单，关键在于表示MIRROR的映射关系，用到了strchr函数

#include <stdio.h>
#include <string.h>

const char c[40] = "ABCDEFGHIJKLMNOPQRSTUVWXYZ123456789";
const char r[40] = "A   3  HIL JM O   2TUVWXY51SE Z  8 ";

int isP(char *d)
{
	int i;
	int l = strlen(d);
	for(i = 0; i <= l/2; ++i)
	{
		if(d[i] != d[l-1-i]) return 0; 
	}
	return 1;
}

int isM(char *d)
{
	int i;
	int temp;
	int l = strlen(d);
	for(i = 0; i <= l/2; ++i)
	{
		temp = strchr(c, d[i]) - c;
		if(d[l-1-i] != r[temp]) return 0;		
	}
	return 1;
}

int main()
{
	char x[25];
	int pc, pm;
	while((scanf("%s", x)) != EOF){
		getchar();
		pc = isP(x);
		pm = isM(x);
		if(pc == 0 && pm == 0) printf("%s -- is not a palindrome.\n", x);
		else if(pc == 0 && pm == 1) printf("%s -- is a mirrored string.\n", x);
		else if(pc == 1 && pm == 0) printf("%s -- is a regular palindrome.\n",x);
		else if(pc == 1 && pm == 1) printf("%s -- is a mirrored palindrome.\n",x);
		printf("\n");

	}
	return 0;
}