FORM的ENCTYPE="multipart/form-data" request.getParameter()获取不到值

tyfengyu

于 2013-08-24 14:05:29 发布

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分类专栏：页面前端文章标签： form表单

本文链接：https://blog.youkuaiyun.com/tyfengyu/article/details/10264279

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本文提供了一种使用Apache Commons FileUpload组件处理multipart/form-data类型的HTTP请求并上传文件的方法，包括下载上传文件相关版本、解析请求、判断文件项类型以及获取参数名和值等关键步骤。

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Situation:

javax.servlet.HttpServletRequest.getParameter(String) returns null when the ContentType is multipart/form-data

Solutions:

1. Download one of the versions of UploadFile from http://jakarta.apache.org/commons/fileupload/
2. Invoke parseRequest(request) on org.apache.commons.fileupload.FileUploadBase which returns list of org.apache.commons.fileupload.FileItem objects. 
3. Invoke isFormField() on each of the FileItem objects. This determines whether the file item is a form paramater or stream of uploaded file. 
4. Invoke getFieldName() to get parameter name and getString() to get parameter value on FileItem if it's a form parameter. Invoke write(java.io.File) on FileItem to save the uploaded file stream to a file if the FileItem is not a form parameter.

这篇文章给出了一个demo，可以参考 http://blog.youkuaiyun.com/liuyuhua0066/article/details/8782716