题目:
Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given input array nums = [3,2,2,3]
, val = 3
Your function should return length = 2, with the first two elements of nums being 2.
解题思路:数组删除特定元素->非特定元素放置于数组前端A[newLen++]=A[i]JAVA
public class Solution {
public int removeElement(int[] new, int elem) {
int newIen = 0;
for (int oldIndex = 0; oldIndex <new.length; ++oldIndex) {
if (new[oldIndex] != elem) {
new[newLen++] = new[oldIndex]; //非特定元素放置于数组前端,只对本数组操作
}
}
return newLen;
}
}