再简单的题目也能被我写的很复杂,是不是想太多了?人家的代码咋就能写那么短呢?
/*
* P1002.cpp
*
* Created on: 2012-4-29
* Author: Administrator
*/
#include <iostream>
#include <cstdlib>
#include <cstring>
using namespace std;
char c[1001];
int sum(char *a, int len_a, char *b, int len_b)
{
int len = 0;
for (len = 0; len < len_a && len < len_b; len++)
{
c[len] += a[len] + b[len];
if (c[len] > 9)
{
c[len+1] += c[len] / 10;
c[len] %= 10;
}
}
for (; len < len_a; len++)
{
c[len] += a[len];
if (c[len] > 9)
{
c[len+1] += c[len] / 10;
c[len] %= 10;
}
}
for (; len < len_b; len++)
{
c[len] += b[len];
if (a[len] > 9)
{
c[len+1] += c[len] / 10;
c[len] %= 10;
}
}
while (c[len] != 0 && len <= 1001)
len ++;
return len - 1;
}
void reverse(char *a, int len)
{
char temp;
for (int i = 0, j = len - 1; i <= j; i++, j--)
{
temp = a[i] - '0';
a[i] = a[j] - '0';
a[j] = temp;
}
}
char a[1001];
char b[1001];
int main(void)
{
int n;
int len_a;
int len_b;
cin >> n;
for (int i = 0; i < n; i++)
{
memset(a, 0, sizeof(char) * 1001);
memset(b, 0, sizeof(char) * 1001);
memset(c, 0, sizeof(char) * 1001);
cin >> a;
cin >> b;
reverse(a, len_a = strlen(a));
reverse(b, len_b = strlen(b));
int len = sum(a, len_a, b, len_b);
cout << "Case "<< i+1 <<":" << endl;
for (int j = len_a-1; j >= 0; j--)
cout << (int)a[j];
cout << " + ";
for (int j = len_b-1; j >= 0; j--)
cout << (int)b[j];
cout << " = ";
for (int j = len; j >=0; j--)
cout << (int)c[j];
cout << endl;
if (i != n-1)
cout << endl;
}
return 0;
}