1.4-09:判断能否被3，5，7整除

#include<iostream>
using namespace std;
int main()
{
	int a;
	cin>>a;
	if(a%3==0) cout<<"3 ";
	if(a%5==0) cout<<"5 ";
	if(a%7==0) cout<<"7";
	if(a%3!=0 && a%5!=0 && a%7!=0) cout<<"n";
}