写了个15位身份证号升级为18位的SQL语句

最新推荐文章于 2025-05-12 16:10:32 发布

原创最新推荐文章于 2025-05-12 16:10:32 发布 · 2.4k 阅读

6 ·

CC 4.0 BY-SA版权

文章标签：

#sql

本文提供了一段SQL脚本，用于将数据库中员工表里的15位身份证号码升级为18位。该脚本根据不同出生年代（18xx年或19xx年）进行转换，并通过特定算法计算校验码。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

-- 15位身份证号升级为18位，适用于18xx年出生的公民
UPDATE 员工表 SET 身份证号=
SUBSTRING(身份证号,1,6)+'18'+SUBSTRING(身份证号,7,9)+
SUBSTRING('10X98765432',
(
CAST(SUBSTRING(身份证号, 1,1) AS INT)*7
+CAST(SUBSTRING(身份证号, 2,1) AS INT)*9
+CAST(SUBSTRING(身份证号, 3,1) AS INT)*10
+CAST(SUBSTRING(身份证号, 4,1) AS INT)*5
+CAST(SUBSTRING(身份证号, 5,1) AS INT)*8
+CAST(SUBSTRING(身份证号, 6,1) AS INT)*4
+1*2
+8*1
+CAST(SUBSTRING(身份证号, 7,1) AS INT)*6
+CAST(SUBSTRING(身份证号, 8,1) AS INT)*3
+CAST(SUBSTRING(身份证号, 9,1) AS INT)*7
+CAST(SUBSTRING(身份证号,10,1) AS INT)*9
+CAST(SUBSTRING(身份证号,11,1) AS INT)*10
+CAST(SUBSTRING(身份证号,12,1) AS INT)*5
+CAST(SUBSTRING(身份证号,13,1) AS INT)*8
+CAST(SUBSTRING(身份证号,14,1) AS INT)*4
+CAST(SUBSTRING(身份证号,15,1) AS INT)*2
)
% 11 + 1, 1)
WHERE LEN(身份证号)=15 AND SUBSTRING(身份证号,13,3) IN ('999','998','997','996')

-- 15位身份证号升级为18位，适用于19xx年出生的公民
UPDATE 员工表 SET 身份证号=
SUBSTRING(身份证号,1,6)+'19'+SUBSTRING(身份证号,7,9)+
SUBSTRING('10X98765432',
(
CAST(SUBSTRING(身份证号, 1,1) AS INT)*7
+CAST(SUBSTRING(身份证号, 2,1) AS INT)*9
+CAST(SUBSTRING(身份证号, 3,1) AS INT)*10
+CAST(SUBSTRING(身份证号, 4,1) AS INT)*5
+CAST(SUBSTRING(身份证号, 5,1) AS INT)*8
+CAST(SUBSTRING(身份证号, 6,1) AS INT)*4
+1*2
+9*1
+CAST(SUBSTRING(身份证号, 7,1) AS INT)*6
+CAST(SUBSTRING(身份证号, 8,1) AS INT)*3
+CAST(SUBSTRING(身份证号, 9,1) AS INT)*7
+CAST(SUBSTRING(身份证号,10,1) AS INT)*9
+CAST(SUBSTRING(身份证号,11,1) AS INT)*10
+CAST(SUBSTRING(身份证号,12,1) AS INT)*5
+CAST(SUBSTRING(身份证号,13,1) AS INT)*8
+CAST(SUBSTRING(身份证号,14,1) AS INT)*4
+CAST(SUBSTRING(身份证号,15,1) AS INT)*2
)
% 11 + 1, 1)
WHERE LEN(身份证号)=15 AND SUBSTRING(身份证号,13,3) NOT IN ('999','998','997','996')