HDU 2066 一个人的旅行（单源最短路）_单源最短路杭电 csdn-优快云博客

本文链接：https://blog.youkuaiyun.com/tick_tock97/article/details/71079716

本文详细介绍Dijkstra算法的基本原理及实现过程，并通过一个具体的编程实例进行演示。文章首先介绍了算法的基本思想，然后展示了如何使用C++语言实现该算法，最后通过解决一个实际问题来验证算法的有效性。

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Dijkstra经典入门题目，有关Dijkstra的学习，可以参考下面这篇文章
http://www.cnblogs.com/skywang12345/p/3711512.html

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
#include<iostream>
#define clear(n,m) memset(n,m,sizeof(n))
using namespace std;
const int MaxInt = 9999999999;
const int MaxNum = 1010;
int map[MaxNum][MaxNum];
int T, S, D, n;
int s[MaxNum];
int d[MaxNum];
int cast[MaxNum];
bool vis[MaxNum];
void Dijkstra()
{
    int minn, pos;
    clear(vis, false);
    vis[0] = true;
    for (int i = 0;i <= n;i++)
    {
        cast[i] = map[0][i];
    }
    for (int i = 0;i < n;i++)
    {
        minn = MaxInt;
        for (int j = 1;j <= n;j++)
        {
            if (cast[j] < minn&&!vis[j])
            {
                pos = j;
                minn = cast[j];
            }
        }
        vis[pos] = true;
        for (int j = 1;j <= n;j++)
        {
            if (cast[pos] + map[pos][j] < cast[j] && !vis[j])
                cast[j] = cast[pos] + map[pos][j];
        }
    }
}
int main()
{
    while (cin >> T >> S >> D)
    {
        n = 0;
        for (int i = 0;i < 1010;i++)
        {
            for (int j = 0;j < 1010;j++)
            {
                map[i][j] = MaxInt;
            }
        }
        for (int i = 0;i < 1010;i++)
        {
            map[i][i] = 0;
        }
        for (int i = 0;i < T;i++)
        {
            int a, b, time;
            cin >> a >> b >> time;
            n = max(max(n, a), b);
            if (time < map[a][b])
                map[a][b] = map[b][a] = time;
        }
        int minn = MaxInt;
        for (int i = 0;i < S;i++)
        {
            cin >> s[i];
            map[0][s[i]] = map[s[i]][0] = 0;
        }
        for (int i = 0;i < D;i++)
        {
            cin >> d[i];
        }
        Dijkstra();
        for (int i = 0;i < D;i++)
        {
            minn = min(minn, cast[d[i]]);
        }
        cout << minn << endl;
    }
    return 0;
}