约瑟夫环的实现-链表方法

//最终实现方法-链表

#include <stdio.h>
#include <malloc.h>

struct node
{
	int nNum,nPassword;
	struct node * next;
};

typedef struct node * LNode;

LNode CreateList(const int num,const int nPwd)
{
	int i;
	LNode head = NULL,p = NULL,q = NULL;

	for(i = 1; i <= num; i ++)
	{
		p = (LNode)malloc(sizeof(struct node));
		p->nNum = i;
		p->nPassword = nPwd;

		if(NULL == head)
		{
			head = p;
		}
		else
		{
			q->next = p;
		}		
		q = p;
	}
	p->next = head;

	return p;//the previous node of the head node
}


void josephus(const int num,const int nPwd,const int nBegin)
{
	if((num <= 0) || (nPwd <= 0) || (nBegin <= 0))
	{
		return ;
	}

	LNode q = CreateList(num,nPwd);
	LNode p = q->next;

	int iNum = num,iCall = nBegin;

	while(iNum --)
	{
		for(int i  = 0;i < iCall - 1; i ++)
		{
			q = p;
			p = p->next;
		}

		q->next = p->next;
		iCall = p->nPassword;
		printf("%3d\n",p->nNum);
		free(p);

		p = q->next;
	}
}

void main()
{
	josephus(100,3,1);
}

//用数组的方法实现

#include <stdio.h>  
  
void main()  
{  
    int i,j,nNum,nDistance,nBegin;//环中总共的人数以及每隔多少人退出  
  
    printf("please input nNum and nBegin:");  
  
    scanf("%d%d",&nNum,&nBegin); 
	
	if((nNum <= 0) || (nBegin <= 0))
	{
		return ;
	}
  
    int *nPassword  = new int [nNum];  
    
	int iStart = 0;//if the password must be during 1 to 24.
	while(iStart < nNum)
	{	  
		printf("the password of NO. %d is(1 ~ 24):",iStart + 1);
        scanf("%d",&nPassword[iStart]);

		if((nPassword[iStart] >= 1) && (nPassword[iStart] <= 24))
		{
			iStart ++;
		}
		else 
		{
			printf("You just input password is incorrect, please enter again!\n");
		}
	}
     
  
    int k = 0;  
      
    nDistance = nBegin;//第一个出环的  
  
    for(i = 0;i < nNum;i ++)  
    {  
        j = 1;  
  
        while(j < nDistance)  
        {  
            while(nPassword[k] == 0)  
            {  
                k = (k + 1) % nNum;  
            }  
            j ++;  
            k = (k + 1) % nNum;  
        }  
        while(nPassword[k] == 0)  
        {  
                k = (k + 1) % nNum;  
        }  
        printf("%3d\n",k + 1);  
  
        nDistance = nPassword[k];  
  
        nPassword[k] = 0;  
    }  
}