1.6 1-13,1-14-优快云博客

本文介绍了一个简单的字符计数与统计程序，该程序能够读取输入并统计非空格、非制表符及非换行符字符的数量，并将这些计数结果存储在一个数组中。此外，还提供了一个更复杂的实现，用于统计ASCII字符出现的频率，并按区间打印出出现的字符。

1-13

pseudocode:

read a word , EOF to stop

if the word is ' ' or '/t' or '/n'

if the pre state is IN

push count to a[i]

add i once

count=0

if the word is not a ' ' and '/t' and '/n'

if the pre state is OUT

update the state to IN

add count once

update lasts to state

#include <stdio.h> #define IN 1 #define OUT 0 int main() { int state=OUT; int lasts=OUT; int c=0; int count=0; int a[10]; int i; for(i=0;i<10;i++) a[i]=0; while(c=getchar()!=EOF){ if(c!=' '&&c!='/t'&&c!='/n'){ if(state==OUT){ state=IN; } count++; } else{ if(lasts==IN){ a[i]=count; count=0; i++; } state=OUT; } lasts=state; }

1-14

#include <stdio.h> #include <cctype.h> #define IN 1 #define OUT 0 #define MAXCHAR 256 #define SIZE 10 int main() { int i,j; int c; int a[MAXCHAR]; for(i=0;i<MAXCHAR;i++) a[i]=0; while(c=getchar()!=EOF){ if(c<=MAXCHAR) ++a[c]; } for(i=0;i<MAXCHAR/SIZE;i++){ if(i==MAXCHAR/SIZE) printf("now printing form %d to %d/n",10*i+j,MAXCHAR); else printf("now printing form %d to %d/n",10*i+j,10*(i+1)+j); for(j=0;j<10;j++){ if(isprint(c)) printf("%c ",a[10*i+j]); } } }