三种类型的二分查找,当查找的元素当中有重复的时候,第一种是返回中间的值,第二种返回的是最左边的值,第三种返回的是最右边的值。
比如在[0,0,0,1,1,1,1,1,2,2]当中查找1,方法1结果是5, 方法二结果是3,方法三结果是7
class Solution:
def binary_search(self, nums, target):
start = 0
end = len(nums) - 1
while start <= end:
mid = (start + end) // 2
if nums[mid] == target:
return mid
elif nums[mid] < target:
start = mid + 1
else:
end = mid - 1
return -1
def binary_search_left(self, nums, target):
start = 0
end = len(nums) - 1
while start < end:
mid = (start + end) // 2
if nums[mid] < target:
start = mid + 1
else:
end = mid
if nums[start] == target:
return start
else:
return -1
def binary_search_right(self, nums, target):
start = 0
end = len(nums) - 1
while start < end:
mid = (start + end) // 2 + 1 # mid+1
if nums[mid] > target:
end = mid - 1
else:
start = mid
if nums[end] == target:
return end
else:
return -1