<?xml version="1.0" encoding="utf-8" ?><rss version="2.0"><channel><title><![CDATA[FDD-Fear Driven Development]]></title><description><![CDATA[祖国啊,我只是一个摆地摊的.]]></description><link>https://blog.youkuaiyun.com/thumb3344</link><language>zh-cn</language><generator>https://blog.youkuaiyun.com/</generator><copyright><![CDATA[Copyright &copy; thumb3344]]></copyright><item><title><![CDATA[ubuntu 10.04 install jdk 7 from sun java jdk]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/8087248</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/8087248</guid><author>thumb3344</author><pubDate>Thu, 18 Oct 2012 20:33:09 +0800</pubDate><description><![CDATA[1. sudo mv ./jdk1.7.0/ /usr/lib/jvm/jdk1.7.0
2. sudo update-alternatives --config java
3. sudo update-alternatives --install /usr/bin/java java /usr/lib/jvm/jdk1.7.0/jre/bin/java 3]]></description><category></category></item><item><title><![CDATA[ubuntu 11.10通过rvm安装Ruby 1.9.2, Rails 3]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/7005610</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/7005610</guid><author>thumb3344</author><pubDate>Sat, 03 Dec 2011 12:02:26 +0800</pubDate><description><![CDATA[1. 安装git
sudo apt-get install build-essential git-core curl
2. 安装rvm 

bash 
3. 配置


echo '[[ -s "$HOME/.rvm/scripts/rvm" ]] && source "$HOME/.rvm/scripts/rvm"' >> ~/.bashrc. ~/.bashrc
4. 安装依]]></description><category></category></item><item><title><![CDATA[Ubuntu下安装insight]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/6752628</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/6752628</guid><author>thumb3344</author><pubDate>Tue, 06 Sep 2011 10:53:27 +0800</pubDate><description><![CDATA[1. 下载安装包
2. ./configure, 

make

3.遇到问题：缺少termcap, 

sudo apt-get install libncurses5-dev

4.遇到问题：
cc1:warning being treated as er]]></description><category></category></item><item><title><![CDATA[Ubuntu下bochs安装]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/6713126</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/6713126</guid><author>thumb3344</author><pubDate>Tue, 23 Aug 2011 21:44:55 +0800</pubDate><description><![CDATA[1. Virtual Box有个增强包，安装之后，在视图中选择Switch Seamless Mode，使用起来非常方便。
2. 准备工作

bochs是由C++编写的，我们要安装相应的编译环境
sudo apt-get install build-essential]]></description><category></category></item><item><title><![CDATA[JDBC中的close方法]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5878905</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5878905</guid><author>thumb3344</author><pubDate>Sun, 12 Sep 2010 12:13:00 +0800</pubDate><description><![CDATA[<br />早上扫了几眼JDBC规范中的Connection,Statement,ResultSet对象，发现了许多小细节。记录于下：<br /> <br />按照scope从小到大排列依次是<br /> <br />ResultSet，Statement，Connection<br /> <br />因此，<br />隐式关闭
：<br />调用conn.close()将使该conn产生的所有statement对象关闭，调用stmt.close将其产生的rs对象关闭。所有引用ResultSet资源的对象]]></description><category></category></item><item><title><![CDATA[算法的时间复杂度]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5861292</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5861292</guid><author>thumb3344</author><pubDate>Fri, 03 Sep 2010 13:51:00 +0800</pubDate><description><![CDATA[<br />注：通篇全是我从不同文章里抄得。 包括：popkiler的博客和丹尼的博客<br /> <br />算法的时间性能分析<br /> <br />一个算法所耗费的时间=算法中每条语句执行时间之和<br />其中，算法中每条语句执行时间=语句频度*执行所需的单位时间。如果一条语句执行时间为单位时间，那么程序执行时间就是所有语句的频度之和。可以看出程序性能的取决于机器指令的性能、速度和编译器产生的代码质量有关。<br /> <br />O(1):<br /> <br /> tmp=m;m=n;n=tm]]></description><category></category></item><item><title><![CDATA[求素数]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5860200</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5860200</guid><author>thumb3344</author><pubDate>Fri, 03 Sep 2010 00:19:00 +0800</pubDate><description><![CDATA[<br />问题：<br />Check whether a given number n > 1 is prime.<br />解答：<br />1.<br />def isPrime(n):   
    for i in range(2, int(pow(n, 0.5))):   
        if n % i == 0:   
            return False   
    return True   <br />2.筛选法<br />import random   
]]></description><category></category></item><item><title><![CDATA[因式分解]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5860138</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5860138</guid><author>thumb3344</author><pubDate>Fri, 03 Sep 2010 00:00:00 +0800</pubDate><description><![CDATA[<br />问题：<br />Write a program that points the factorization of a given integer n > 0.(In other words, it should print prime numbers whose product is equal to n;if n=1, nothing should be printed)<br />解答：<br />1.<br /> k=n
while k!=1:
    t = 2
    whil]]></description><category></category></item><item><title><![CDATA[求平方]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5860123</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5860123</guid><author>thumb3344</author><pubDate>Thu, 02 Sep 2010 23:48:00 +0800</pubDate><description><![CDATA[<br />问题：<br />Write a program that point the squares of  the natural number 0,1,...,n.<br />解答：<br />1.<br /> <br /> k=0
while not (k>n):
    print k*k
    k=k+1<br />2.(n-1)2=n2-2n+1则n2=(n-1)2+2n-1<br />k=0
while not (k>n):
    k=k+1
    square = s]]></description><category></category></item><item><title><![CDATA[求GCD(a,b)]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5859192</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5859192</guid><author>thumb3344</author><pubDate>Thu, 02 Sep 2010 16:33:00 +0800</pubDate><description><![CDATA[<br />问题：<br />Two nonnegative integers a and b are not both zero. Compute GCD(a,b), the greatest common divisor of a and b.<br />解答：<br />1. <br />k = max(a,b)
while not (a%k==0 and b%k==0):
    k = k-1<br />2.Euclid's algorithm<br />m,n=a,b
while not ]]></description><category></category></item><item><title><![CDATA[求1/0!+1/1!+...+1/n!]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5858091</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5858091</guid><author>thumb3344</author><pubDate>Thu, 02 Sep 2010 12:53:00 +0800</pubDate><description><![CDATA[<br />问题：<br />非负数n，求1/0!+1/1!+...+1/n!。<br />解答：<br />1<br />k,a,sum=N,1,0
while k>0:
    k=k-1
    a=a*k
    sum=sum+1/a]]></description><category></category></item><item><title><![CDATA[求fibonacci]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5856943</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5856943</guid><author>thumb3344</author><pubDate>Thu, 02 Sep 2010 00:06:00 +0800</pubDate><description><![CDATA[问题：a0=0,a1=1...ak = ak-1+ak-2 ，求an 解答：1. 递归def fib(n):
    if n == 0:
        return 0
    elif n == 1:
        return 1
    else:
        return fib(n-1) + fib(n-2)2. 迭代    a, b = 0, 1
    while b ]]></description><category></category></item><item><title><![CDATA[求n!]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5856896</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5856896</guid><author>thumb3344</author><pubDate>Wed, 01 Sep 2010 23:46:00 +0800</pubDate><description><![CDATA[问题：求非负整数n的阶乘。 解答：sum,k = 1,n
while k>0:
    sum = sum*k
    k = k-1]]></description><category></category></item><item><title><![CDATA[求商和余数]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5856873</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5856873</guid><author>thumb3344</author><pubDate>Wed, 01 Sep 2010 23:31:00 +0800</pubDate><description><![CDATA[<br />问题：<br />有非负数a,和正数d，求商q和余数r？两者的英文单词又是什么？不能用%和/运算符。<br /> 解答：<br />1. 商：quotient,余数：remainder<br /> <br />     q,r=0,a
    while not (r<d):
        r = r-d
        q = q+1<br /> ]]></description><category></category></item><item><title><![CDATA[求a*b,a+b]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5856844</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5856844</guid><author>thumb3344</author><pubDate>Wed, 01 Sep 2010 23:11:00 +0800</pubDate><description><![CDATA[问题：a,b为非负整型，求a*b。只能用+、-、=、!=运算符。解答：1.    k,c=0,1
    while k ]]></description><category></category></item><item><title><![CDATA[求a的N次方]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5856793</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5856793</guid><author>thumb3344</author><pubDate>Wed, 01 Sep 2010 22:41:00 +0800</pubDate><description><![CDATA[问题：假设a是整型，N为非负整型。求a的N次方b解决：1.     k=0
    b=1
    while k  2.    k=N
    b=1
    while k > 0:
        b = a*b 
        k = k-1
]]></description><category></category></item><item><title><![CDATA[值交换]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5856750</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5856750</guid><author>thumb3344</author><pubDate>Wed, 01 Sep 2010 22:29:00 +0800</pubDate><description><![CDATA[问题：假设有两个整型变量a1、a2，值分别是v1,v2 如何才能交换他们的值？解答：1. temp = a1 #temp此时为v1a1 = a2 #a1此时为v2b2 = temp #a2此时为v12.a1 = a1+a2 #a1此时为v1+v2a2 = a1-a2 #a2 此时为v1a1 = a1-a2 #a1 此时为v2]]></description><category></category></item><item><title><![CDATA[redvex + netstuff]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5827801</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5827801</guid><author>thumb3344</author><pubDate>Sat, 21 Aug 2010 00:34:00 +0800</pubDate><description><![CDATA[<br />******************************<br />*Diablo 2 Packet Sniffing 101*<br />******************************<br />*By: REN3G4DE *<br />*Written For: Blizz Sector *<br />*Version: 1.11b *<br />******************************<br /><br />First lets start with ]]></description><category></category></item><item><title><![CDATA[Ubuntu下Mongrel和mongrel cluster的配置]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5732472</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5732472</guid><author>thumb3344</author><pubDate>Tue, 13 Jul 2010 18:17:00 +0800</pubDate><description><![CDATA[步骤写得挺详细。见：http://cloudservers.rackspacecloud.com/index.php/Ubuntu_-_Mongrel_and_mongrel_cluster]]></description><category></category></item><item><title><![CDATA[理解python的修饰符@]]></title><link>https://blog.youkuaiyun.com/thumb3344/article/details/5645124</link><guid>https://blog.youkuaiyun.com/thumb3344/article/details/5645124</guid><author>thumb3344</author><pubDate>Thu, 03 Jun 2010 16:29:00 +0800</pubDate><description><![CDATA[<br />由于是从Java转过来的，看见python中有@修饰符时，很迷惑。看了一些网上的资料，感觉叙述的不太容易理解。自己想写一篇易于理解的。先来看一段程序：<br />def spamrun(fn):
    def sayspam(*args):
        a,b =args
        c,d = a*5, b*5
        print c,d
        return fn(c,d)
    print 'note!'
    return sayspam
@]]></description><category></category></item></channel></rss>