执行以下语句会打印出?
int arr[] = {6, 7, 8, 9 ,10};
int* ptr = arr;
*(ptr++) += 123;
cout<<*ptr<<endl;
先看看运算符的优先级,一般容易考察的是红色的这几个:
| Precedence | Operator | Description | Associativity |
|---|---|---|---|
| 1 | :: | Scope resolution | Left-to-right |
| 2 |
++ -- | Suffix/postfix increment and decrement (a++) | |
() | Function call | ||
[] | Array subscripting | ||
. | Element selection by reference | ||
−> | Element selection through pointer | ||
| 3 |
++ -- | Prefix increment and decrement (++a) | Right-to-left |
+ − | Unary plus and minus | ||
! ~ | Logical NOT and bitwise NOT | ||
(type) | Type cast | ||
* | Indirection (dereference) | ||
& | Address-of | ||
sizeof | Size-of | ||
new, new[] | Dynamic memory allocation | ||
delete, delete[] | Dynamic memory deallocation | ||
| 4 | .* ->* | Pointer to member | Left-to-right |
| 5 | * / % | Multiplication, division, and remainder | |
| 6 | + − | Addition and subtraction | |
| 7 | << >> | Bitwise left shift and right shift | |
| 8 |
< <= | For relational operators < and ≤ respectively | |
> >= | For relational operators > and ≥ respectively | ||
| 9 | == != | For relational = and ≠ respectively | |
| 10 | & | Bitwise AND | |
| 11 | ^ | Bitwise XOR (exclusive or) | |
| 12 | | | Bitwise OR (inclusive or) | |
| 13 | && | Logical AND | |
| 14 | || | Logical OR | |
| 15 |
?: | Ternary conditional | Right-to-left |
= | Direct assignment (provided by default for C++ classes) | ||
+= −= | Assignment by sum and difference | ||
*= /= %= | Assignment by product, quotient, and remainder | ||
<<= >>= | Assignment by bitwise left shift and right shift | ||
&= ^= |= | Assignment by bitwise AND, XOR, and OR | ||
| 16 | throw | Throw operator (for exceptions) | |
| 17 | , | Comma | Left-to-right |
所以这句应该解释为:
*(ptr++) += 123;*ptr = *ptr + 123; ptr++; 括号中的内容先执行,得到前一语句;ptr再进行自增;ptr的自增应该是在第一条语句执行之后发生的,这样才合理,否则*(++ptr) += 123的执行结果就不好解释了,写编译器的人肯定也需要语句执行的结果合理才能自圆其说的!
答案: 7
本文详细解析了一段C++代码片段的执行流程,重点解释了指针操作和算术运算如何影响数组元素的值,并最终输出结果。
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