1.System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo(); this.txtCashAmt.Text = strCashAmt.ToString("N",provider); //再利用ToString函数格式化小数位数 2.保留N位,四舍五入 . decimal d= decimal.Round(decimal.Parse("0.55555"),2); 3.保留N位四舍五入 Math.Round(0.55555,2) 4,保留N位四舍五入 5.保留N位四舍五入 string result = String.Format("{0:N2}", 0.55555);//2位 string result = String.Format("{0:N3}", 0.55555);//3位 6. 保留N位四舍五入 (不错) double s=0.55555; C#下如果显示保留小数位数,及百分号的解决方法: 1、用NumberFormatInfo类来解决: provider.PercentDecimalDigits = 2;//小数点保留几位数. 2、用toString方法.: if (task == 0) double db = (hcount / task) * 100; if (hcount >= task) string str1 = String.Format("{0:N1}",56789); //result: 56,789.0
provider.NumberDecimalDigits =intDecLength; //要设定的小数位数
double strCashAmt=Convert.ToDouble(this.txtCashAmt.Text); //先把控件內的值转成double
double dbdata = 0.55555;
string str1 = dbdata.ToString("f2");//fN 保留N位,四舍五入
result=s.ToString("#0.00");//点后面几个0就保留几位
System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();
provider.PercentPositivePattern = 2;//百分号出现在何处.
double result = (double)1 / 3;//一定要用double类型.
Response.Write(result.ToString("P", provider));
public string getRate(double hcount, double task)
{
string rValue;
string temp = "";
{
task = 1;
}
{
rValue = "100%";
}
else
{
rValue = db.ToString("#0.#0") + "%";
}
return rValue;
}
string str2 = String.Format("{0:N2}",56789); //result: 56,789.00
string str3 = String.Format("{0:N3}",56789); //result: 56,789.000
string str8 = String.Format("{0:F1}",56789); //result: 56789.0
string str9 = String.Format("{0:F2}",56789); //result: 56789.00
string str11 =(56789 / 100.0).ToString("#.##"); //result: 567.89
string str12 =(56789 / 100).ToString("#.##"); //result: 567
C#保留小数位数的方法集锦
最新推荐文章于 2023-09-04 14:58:56 发布