- <span style="font-size:24px;"><strong>需求:在项目中想要添加一个长按Cell弹出UIMenuController的功能</strong></span>

要实现长按弹出菜单栏需要做到以下三点:
1.在view(cell)或者viewController中调用-becomeFirstResponder方法;
2.你的view获得或者view controller需要实现 -canBecomeFirstResponder 方法,返回YES;
3.你的view获得或者view controller需要实现-canPerformAction:action withSender:sender 方法来隐藏或者现实响应的item;
cell中关键代码展示:
1.添加longpress事件
- -(instancetype)initWithStyle:(UITableViewCellStyle)style reuseIdentifier:(NSString *)reuseIdentifier{
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- if (self=[super initWithStyle:style reuseIdentifier:reuseIdentifier]) {
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- [self addGestureRecognizer: [[UILongPressGestureRecognizer alloc]initWithTarget:selfaction:@selector(longTap:)]];
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- }
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- return self;
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- }
2.处理长按事件
- -(void)longTap:(UILongPressGestureRecognizer *)longRecognizer
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- {
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- if (longRecognizer.state==UIGestureRecognizerStateBegan) {
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- [self becomeFirstResponder];
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- UIMenuController *menu=[UIMenuController sharedMenuController];
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- UIMenuItem *copyItem = [[UIMenuItem alloc] initWithTitle:@"复制" action:@selector(copyItemClicked:)];
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- UIMenuItem *resendItem = [[UIMenuItem alloc] initWithTitle:@"转发" action:@selector(resendItemClicked:)];
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- [menu setMenuItems:[NSArray arrayWithObjects:copyItem,resendItem,nil]];
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- [menu setTargetRect:self.bounds inView:self];
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- [menu setMenuVisible:YES animated:YES];
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- }
-
- }
3.实现默认方法
- #pragma mark 处理action事件
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- -(BOOL)canPerformAction:(SEL)action withSender:(id)sender{
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- if(action ==@selector(copyItemClicked:)){
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- return YES;
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- }else if (action==@selector(resendItemClicked:)){
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- return YES;
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- }
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- return [super canPerformAction:action withSender:sender];
-
- }
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- #pragma mark 实现成为第一响应者方法
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- -(BOOL)canBecomeFirstResponder{
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- return YES;
-
- }
4.处理item点击事件
- #pragma mark method
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- -(void)resendItemClicked:(id)sender{
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- NSLog(@"转发");
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- //通知代理
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- }
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- -(void)copyItemClicked:(id)sender{
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- NSLog(@"复制");
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- // 通知代理
-
- }