【Python小白学习】文本词频统计

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最新推荐文章于 2023-10-25 22:16:54 发布

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博客主要进行了英文《Hamlet》的词频统计以及中文《三国演义》的人物出场统计，并尝试将词频和人物相关联，以面向特定问题展开分析。

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英文_Hamlet英文词频统计

#CalHamlet.py

def getText():
    txt = open("hamlet.txt", "r").read()
    txt = txt.lower()
    for ch in '!"#$%&()*+,-./:;<=>?@[\\]^_‘{|}~':
        txt = txt.replace(ch, " ")
    return txt

hamletText = getText()
words = hamletTxt.spilt()       #words是一个列表类型
counts = {}                     #counts是一个字典类型
for word in words:
    counts[word] = counts.get(word, 0)

items = list(counts.items())
items.sort(key = lambda x :x[1], reverse = True)    #reverse = True：从大到小排序

for i in range(10):
    word, count = items[i]
    print("{0:<10}{1:>5}".format(word, count))

中文_《三国演义》人物出场统计

将词频和人物相关联，面向问题

#CalThreeKingdoms.py

import jieba

txt = open("threekingdoms.txt", "r", encoding = "utf-8").read()
excludes = {"将军", "却说", "荆州", "二人", "不可", "不能", "如此", "商议", "主公"}
words = jieba.lcut(txt)
counts = {}                     #counts是一个字典类型
for word in words:
    if len(word) == 1:
        continue
    elif word == "诸葛亮" or word == "孔明曰":
        rword == "孔明"
    elif word == "关公" or word == "云长":
        rword = "关羽"
    elif word == "玄德" or word == "玄德曰":
        rword = "刘备"
    elif word == "孟德" or word == "丞相":
        rword = "曹操"
    else:
        rword = word
    counts[rword] = counts.get(rword, 0) + 1
for word in excludes:
    del counts[word]
items = list(counts.items())
items.sort(key = lambda x :x[1], reverse = True)    #reverse = True：从大到小排序

for i in range(10):
    word, count = items[i]
    print("{0:<10}{1:>5}".format(word, count))