488 - Triangle Wave
Time limit: 3.000 seconds
In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.
Input and Output
The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.
Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.
For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.
For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.
The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.
NOTE: There is a blank line after each separate waveform, excluding the last one.
Sample Input
1 3 2
Sample Output
1 22 333 22 1 1 22 333 22 1
完整代码:
/*0.065s*/
#include <cstdio>
int main(void)
{
int T, A, F;
int i, j, k, l;
scanf("%d", &T);
for (i = 0; i < T; i++)
{
if (i)
putchar('\n');
scanf("%d%d", &A, &F);
for (j = 0; j < F; j++)
{
if (j)
putchar('\n');
for (k = 0; k < A; k++)
{
for (l = 0; l <= k; l++)
putchar('1' + k);
putchar('\n');
}
for (k = A - 2; k >= 0; k--)
{
for (l = 0; l <= k; l++)
putchar('1' + k);
putchar('\n');
}
}
}
return 0;
}

本文介绍了一个简单的程序,用于根据指定的振幅和频率生成三角波形。输入包括振幅和频率两个整数,输出为一系列按指定振幅变化的三角波形。每个波形由数字填充,表示该行的高度。
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