UVA, 382 Perfection

Sample Input

15 28 6 56 60000 22 496 0

Sample Output

PERFECTION OUTPUT
   15  DEFICIENT
   28  PERFECT

    6  PERFECT
   56  ABUNDANT
60000  ABUNDANT

   22  DEFICIENT
  496  PERFECT

END OF OUTPUT 

#include<cstdio>

#include<cstring>

#include<stack>

#include<iostream>

using namespace std;

int sum(int m){

int sum = 0;

for(int i = 1; i <= m/2; i++){

if(m % i == 0) sum += i;//做除法运算的时候一定要小心分母是否为0

}

return sum;

};

int main()

{

int n;

cout<< "PERFECTION OUTPUT"<< endl;

while(cin >> n){

if(n == 0) break;

int t = sum(n);

printf("%5d",n);

if(t == n) cout << "  PERFECT" << endl;

else if(t > n) cout << "  ABUNDANT" << endl;

else cout << "  DEFICIENT" << endl;

}

cout << "END OF OUTPUT" << endl;

return 0;

}

1. 原来提前把PERFECTION OUTPUT 输出来也可以AC