输入一个日期判断这个日期的下一天是哪一天，判断这个日期是此年中的第多少天

最新推荐文章于 2024-03-13 12:00:06 发布

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这篇文章介绍了如何使用Java编程语言实现判断并获取给定日期的下一天，通过示例代码展示了如何处理闰年和不同月份天数规则。

判断一个日期的下一天是哪一天

package com.qianfeng.day17;

public class Date {
	public static void main(String[] args) {
		System.out.println(dataFangfa(2000, 2, 29));
	}
	
	public static String dataFangfa(int year, int month, int day) {
		if (year >= 1900 && year <= 2050 && month >= 1 && month <= 12 && day >= 1 && day <= 31) {
			if (month == 4 || month == 6 || month == 9 || month == 11) {
				if (day >= 1 && day < 30) {
					day++;
				} else if (day == 30) {
					month++;
					day = 1;
				}
			} else if (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10) {
				if (day >= 1 && day < 31) {
					day++;
				} else if (day == 31) {
					month++;
					day = 1;
				}
			} else if (month == 12) {
				if (day >= 1 && day < 31) {
					day++;
				} else if (day == 31) {
					year++;
					month = 1;
					day = 1;
				}
			} else if (month == 2) {
				if (year % 4 == 0 && (year % 400 == 0 || year % 100 != 0)) {
					if (day >= 1 && day < 29) {
						day++;
					} else if (day == 29) {
						month++;
						day = 1;
					}
				} else {
					if (day >= 1 && day < 28) {
						day++;
					} else if (day == 28) {
						month++;
						day = 1;
					}
				}
			}
		} else {
			year = 0;
			month = 0;
			day = 0;
			System.out.println("Error:您的输入有误！");
		}
		return year + "-" + month + "-" + day;
	}

}

判断这个日期是此年中的第多少天

package com.qianfeng.day17;

public class Test02 {
	public static void main(String[] args) {
		System.out.println(dataFangfa(2020, 3, 2));
	}

	public static int dataFangfa(int year, int month, int day) {
		int numbers = 0;

		switch (month) {
		case 12:
			if (month == 12) {
				numbers += day;
			}else {
				numbers += 31;
			}
		case 11:
			if (month == 11) {
				numbers += day;
			}else {
				numbers += 30;
			}
		case 10:
			if (month == 10) {
				numbers += day;
			}else {
				numbers += 31;
			}
		case 9:
			if (month == 9) {
				numbers += day;
			}else {
				numbers += 30;
			}
		case 8:
			if (month == 8) {
				numbers += day;
			}else {
				numbers += 31;
			}
		case 7:
			if (month == 7) {
				numbers += day;
			}else {
				numbers += 31;
			}
		case 6:
			if (month == 6) {
				numbers += day;
			} else {
				numbers += 30;
			}
		case 5:
			if (month == 5) {
				numbers += day;
			} else {
				numbers += 31;
			}
		case 4:
			if (month == 4) {
				numbers += day;
			} else {
				numbers += 30;
			}
		case 3:
			if (month == 3) {
				numbers += day;
			} else {
				numbers += 31;
			}
		case 2:
			if (month == 2) {
				numbers = numbers + day;
			} else {
				if (year % 4 == 0 && (year % 400 == 0 || year % 100 != 0)) {
					numbers += 29;
				} else {
					numbers += 28;
				}
			}
		case 1:
			if (month == 12) {
				numbers += day;
			}
			numbers += 31;

		}
		return numbers;
	}
}