https://blog.youkuaiyun.com/sunmanzthzh-cnhttps://blog.youkuaiyun.com/https://blog.youkuaiyun.com/sunmanzth/article/details/7904763https://blog.youkuaiyun.com/sunmanzth/article/details/7904763sunmanzthFri, 24 Aug 2012 17:03:49 +0800https://blog.youkuaiyun.com/sunmanzth/article/details/7865267https://blog.youkuaiyun.com/sunmanzth/article/details/7865267sunmanzthTue, 14 Aug 2012 15:39:48 +0800https://blog.youkuaiyun.com/sunmanzth/article/details/7865162https://blog.youkuaiyun.com/sunmanzth/article/details/7865162sunmanzthTue, 14 Aug 2012 15:27:11 +0800https://blog.youkuaiyun.com/sunmanzth/article/details/6950034https://blog.youkuaiyun.com/sunmanzth/article/details/6950034sunmanzthTue, 08 Nov 2011 21:16:44 +0800https://blog.youkuaiyun.com/sunmanzth/article/details/6902458https://blog.youkuaiyun.com/sunmanzth/article/details/6902458sunmanzthTue, 25 Oct 2011 01:25:03 +0800https://blog.youkuaiyun.com/sunmanzth/article/details/6860157https://blog.youkuaiyun.com/sunmanzth/article/details/6860157sunmanzthMon, 10 Oct 2011 18:07:07 +0800https://blog.youkuaiyun.com/sunmanzth/article/details/6298711https://blog.youkuaiyun.com/sunmanzth/article/details/6298711sunmanzthSat, 02 Apr 2011 16:33:00 +0800 const引用的作用：
1. 避免不必要的复制。2. 限制不能修改对象。
const 引用的是对象时只能访问该对象的const 函数例：
Class A{public:    void constFunc() const;    void nonConstFunc();};
A a;const A& refA = a;refA.constFunc(); // good,因为该函数不会修改对象refA.nonConstFunc(); //can't]]>https://blog.youkuaiyun.com/sunmanzth/article/details/6230878https://blog.youkuaiyun.com/sunmanzth/article/details/6230878sunmanzthTue, 08 Mar 2011 10:38:00 +0800
一。创建SQL SERVER 2008解决方案
    1.在SQL SERVER 2008中，点击文件->新建->项目，输入一个项目名，点击确定即创建了一个解决方案
    2.在解决方案资源管理器窗口中选中连接文件夹->右键->新建连接，添加一个要对其进行存储过程版本控制的数据库的连接
    3.添加好数据库连接后，双击该连接，则会在查询文件夹下新建一个SQLQuery1.sql文件，把这个文件名改为 “要进行版本控制的存储过程名.sql”，然后把]]>https://blog.youkuaiyun.com/sunmanzth/article/details/6221103https://blog.youkuaiyun.com/sunmanzth/article/details/6221103sunmanzthThu, 03 Mar 2011 16:47:00 +0800https://blog.youkuaiyun.com/sunmanzth/article/details/6178213https://blog.youkuaiyun.com/sunmanzth/article/details/6178213sunmanzthFri, 11 Feb 2011 10:02:00 +0800在网上找资料的时候看到一种删除list中元素的方法，如下
std::list subscribers_;
subscribers_.erase(std::remove(subscribers_.begin(),subscribers_.end(), &subscriber),
         subscribers_.end());
 
其实对于list，完全可以用list::remove函数直接移除元素，效果是一]]>https://blog.youkuaiyun.com/sunmanzth/article/details/6143600https://blog.youkuaiyun.com/sunmanzth/article/details/6143600sunmanzthSun, 16 Jan 2011 01:20:00 +0800https://blog.youkuaiyun.com/sunmanzth/article/details/6136238https://blog.youkuaiyun.com/sunmanzth/article/details/6136238sunmanzthThu, 13 Jan 2011 20:39:00 +0800