hdu 1062 Text Reverse

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本文介绍了一个简单的编程问题：如何将一行包含多个单词的文本中每个单词逆序输出。通过一个具体的C++代码示例，文章展示了如何使用基本的字符串操作技巧来解决这个问题，包括读取输入、处理空格分隔的单词并逆序输出。

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给个测试数据：

ab bc

ba cb

注意输出地空格

http://acm.hdu.edu.cn/showproblem.php?pid=1062

Problem Description

Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single line with several words. There will be at most 1000 characters in a line.

Output

For each test case, you should output the text which is processed.

Sample Input

  
   3
olleh !dlrow
m'I morf .udh
I ekil .mca

Sample Output

  
   hello world!
I'm from hdu.
I like acm.


   
    
     Hint
    
Remember to use getchar() to read '\n' after the interger T, then you may use gets() to read a line and process it.

   
  
  
    
  
  
    
  
  
   
    #include <iostream>
using namespace std;
#include <string.h>
int main()
{
    int n,i,l,k,j;
    char a,b[1000];
    cin>>n;
    getchar();// 读取一个回车
    while(n--)
    {
        gets(b);
        l=strlen(b);
        k=0;
        for(i=0;i<l;i++)
        {   if(b[i]==32)\\如果是空格的话就输出，并且标记k指向后一个
              {
              cout<<" ";
              k=i+1;
        }
        else
            if(b[i+1]==32||b[i+1]=='\0')\\这个开始就写错了，还要判断最后一个是不是结束
            {
                for(j=i;j>=k;j--)
                    cout<<b[j];
                k=i+1;
            }
        }
            cout<<endl;
    }