vc怎样通过进程名获取进程的工作目录.

先用OpenProcess()函数将进程打开后，利用EnumProcessModules()函数枚举该进程的模块，利用GetModuleFileNameEx()函数就能取得该进程的路径

#include <stdio.h>
#include <windows.h>
#include "PSAPI.H"
#pragma comment( lib, "PSAPI.LIB" )

int main(void)
{

     DWORD processid[1024],needed,processcount,i;
     HANDLE hProcess;
    HMODULE hModule;
    char path[MAX_PATH] = "";

    char temp[256];

    printf("ShowProcessPath with [Process Status API]/n");

    EnumProcesses(processid, sizeof(processid), &needed);
    processcount=needed/sizeof(DWORD);

    for (i=0;i<processcount;i++)
   {
        hProcess=OpenProcess(PROCESS_QUERY_INFORMATION | PROCESS_VM_READ,false,processid[i]);
        if (hProcess)
       {
             EnumProcessModules(hProcess, &hModule, sizeof(hModule), &needed);
             GetModuleFileNameEx(hProcess, hModule, path, sizeof(path));
             GetShortPathName(path,path,256);
             itoa(processid[i],temp,10);
             printf("%s --- %s/n",path,temp);
        }
        else

        {
           printf("Failed!!!/n");

        }
     }

     CloseHandle(hProcess);
     CloseHandle(hModule);

     itoa(processcount,temp,10);
     printf("/nProcess Count:%s/n/n",temp);

     return 0;
}