Accept: 264 Submit: 456
Time Limit: 1000 mSec Memory Limit : 32768 KB
Problem Description
You are given a rectangular map of a continent. The map is a grid of squares, each square has a color. A country is a connected set of squares (squares are connected if they share an edge) that have the same color. Neighboring countries have different colors. Find the size (in squares) of the largest country.
There will be at least one country in the map.
There will be at least one country in the map.
Input
Input data will be provided as standard input to the program. The first line of input contains the number of test cases (<=10). Each test case begins with a line containing two numbers W and H, the width and height of the map, separated by a single space, 1 <= W,H <= 10. The next H lines contain W characters each | they describe the map. Colors are represented by the letters A-Z. Water (no country) is represented by a dot.
Output
For each test case output one line containing the size of the largest country.
Sample Input
1
6 5
...BBB
.AAAAB
..BBA.
..BB..
......
Sample Output
5
Source
FOJ月赛-2007年5月 我的程序:
#include<iostream>
using namespace std;
typedef struct{
char val;
bool flag;
}VF;
VF map[100][100];
char ch;
int thisarea=0;
int m,n;
int visit(int i,int j)
{
if(map[i][j].flag==false && map[i][j].val!='.' && map[i][j].val==ch)
{
map[i][j].flag=true;
thisarea++;
if(i-1>=0)
visit(i-1,j);
if(i+1<m)
visit(i+1,j);
if(j-1>=0)
visit(i,j-1);
if(j+1<n)
visit(i,j+1);
}
return thisarea;
}
int main()
{
int i,j,count,area;
cin>>count;
while(count>0)
{
area=0;
cin>>n>>m;
for(i=0;i<m;i++)
for(j=0;j<n;j++)
{
cin>>map[i][j].val;
map[i][j].flag=false;
}
for(i=0;i<m;i++)
for(j=0;j<n;j++)
{
ch=map[i][j].val;
thisarea=0;
visit(i,j);
if(thisarea>area)
area=thisarea;
}
count--;
cout<<area<<endl;
}
return 0;
}
using namespace std;
typedef struct{
char val;
bool flag;
}VF;
VF map[100][100];
char ch;
int thisarea=0;
int m,n;
int visit(int i,int j)
{
if(map[i][j].flag==false && map[i][j].val!='.' && map[i][j].val==ch)
{
map[i][j].flag=true;
thisarea++;
if(i-1>=0)
visit(i-1,j);
if(i+1<m)
visit(i+1,j);
if(j-1>=0)
visit(i,j-1);
if(j+1<n)
visit(i,j+1);
}
return thisarea;
}
int main()
{
int i,j,count,area;
cin>>count;
while(count>0)
{
area=0;
cin>>n>>m;
for(i=0;i<m;i++)
for(j=0;j<n;j++)
{
cin>>map[i][j].val;
map[i][j].flag=false;
}
for(i=0;i<m;i++)
for(j=0;j<n;j++)
{
ch=map[i][j].val;
thisarea=0;
visit(i,j);
if(thisarea>area)
area=thisarea;
}
count--;
cout<<area<<endl;
}
return 0;
}