题目:Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn’t matter what you leave beyond the new length.
Example:
Given input array nums = [3,2,2,3], val = 3
Your function should return length = 2, with the first two elements of nums being 2.
题意:去掉list中值等于val的元素,其他若干元素依次保存在list前若干位置。不用新的空间,使用连续内存。代码和上一题类似。
python AC 56ms。
class Solution(object):
def removeElement(self, nums, val):
"""
:type nums: List[int]
:type val: int
:rtype: int
"""
k=len(nums)
if k==0:
return None
p=0
for i in range(k):
if nums[i]!=val:
nums[p]=nums[i]
p+=1
return p

本文介绍了一种在不使用额外空间的情况下从数组中移除指定值的算法,并提供了Python实现。该方法通过双指针技术在原地修改数组,达到移除特定值的目的。
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