Given a list, rotate the list to the right by k places, where k is non-negative.
For example:
Given 1->2->3->4->5->NULL
and k = 2
,
return 4->5->1->2->3->NULL
.
Subscribe to see which companies asked this question
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* rotateRight(ListNode* head, int k) {
int len = 0;
ListNode *l = head;
ListNode *ret = NULL;
if(head == NULL) return ret;
while(l != NULL) {
len++;
l = l->next;
}
k = k%len;
if(k == 0) return head;
int kk = len-k;
kk = kk-1;
l = head;
while(kk--) {
l = l->next;
}
ListNode *next = l->next;
l->next = NULL;
ret = next;
for(; next->next!=NULL; next=next->next);
next->next = head;
return ret;
}
};