Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given input array nums = [3,2,2,3], val = 3
Your function should return length = 2, with the first two elements of nums being 2.
#include <iostream>
#include <cstdio>
#include <vector>
using namespace std;
class Solution {
public:
int removeElement(vector<int>& nums, int val) {
int cnt = 0;
for (int i = 0; i < nums.size(); ++i)
{
if(nums[i] == val) continue;
nums[cnt] = nums[i];
cnt++;
}
return cnt;
}
}
本文介绍了一种在不使用额外数组的情况下从数组中移除指定值的方法,并保持内存使用为常数。通过一个示例展示了如何实现这一过程:给定数组 [3,2,2,3] 和值 3,函数返回新长度 2 并将数组的前两个元素更新为 2。
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