Implement atoi to convert a string to an integer.
Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the possible input cases.
Notes: It is intended for this problem to be specified vaguely (ie, no given input specs). You are responsible to gather all the input requirements up front.
Update (2015-02-10):
The signature of the C++ function had been updated. If you still see your function signature
accepts a const char * argument, please click the reload button to
reset your code definition.
class Solution:
def atoi(self, str):
lens = len(str);
if lens == 0:
return 0;
i = 0;
cnt = 1;
sum = 0;
while i < lens:
if str[i] == ' ':
i += 1;
else:
break;
if str[i] == '-':
cnt = -1;
i += 1;
elif str[i] == '+':
cnt = 1;
i += 1;
elif str[i] < '0' or str[i] > '9':
return 0;
while i < lens and str[i] >= '0' and str[i] <= '9':
sum = sum * 10 + ord(str[i])-ord('0');
i += 1;
sum = sum*cnt;
if sum > 0x7fffffff:
sum = 0x7fffffff;
if sum < -2 ** 31:
sum = -2 ** 31;
return sum;
本文详细解析了atoi函数的实现逻辑,包括如何处理输入字符串中的空格、符号和数字,以及如何进行整数边界检查。通过案例分析,帮助开发者理解atoi函数的核心原理并提升编程技巧。
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