很简单很直接的线段树。
/*
* Author: stormdpzh
* HDOJ: 4217 Data Structure?
* Time: 2012/4/25 12:09:16
*/
#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <cmath>
#include <vector>
#include <queue>
#include <stack>
#include <set>
#include <algorithm>
#include <functional>
#define sz(v) ((int)(v).size())
#define rep(i, n) for(int i = 0; i < n; i++)
#define repf(i, a, b) for(int i = a; i <= b; i++)
#define out(n) printf("%d", n)
#define wh(n) while(scanf("%d", &n) != EOF)
#define whz(n) while(scanf("%d", &n) != EOF && n != 0)
#define int64 long long
using namespace std;
const int Max = 262150;
int n, k;
int num[4 * Max];
void build(int l, int r, int i)
{
num[i] = r - l + 1;
if(r == l)
return;
int mid = (l + r) >> 1;
build(l, mid, i << 1);
build(mid + 1, r, i * 2 + 1);
}
int search(int l, int r, int tmp, int i)
{
num[i]--;
if(l == r)
return l;
int mid = (l + r) >> 1;
int tmp_res;
if(num[i << 1] >= tmp)
return search(l, mid, tmp, i << 1);
else
return search(mid + 1, r, tmp - num[i << 1], i * 2 + 1);
}
int main()
{
int t;
scanf("%d", &t);
int ans = 1;
while(t--) {
scanf("%d%d", &n, &k);
build(1, n, 1);
int64 res = 0;
rep(i, k) {
int tmp;
scanf("%d", &tmp);
res += (int64)search(1, n, tmp, 1);
}
printf("Case %d: %I64d\n", ans++, res);
}
return 0;
}