public class test {
static int[] A = { 3, 10, 9, 8, 5, 6, 1, 2, 7, 4 };
public static void Merge(int[] B, int i1, int j1, int i2, int j2) {
int n = j2 - i1 + 1;
int[] temp = new int[n];
int k = 0, i = i1, j = i2;
while (i <= j1 && j <= j2) {
if (B[i] <= B[j]) {
temp[k++] = B[i++];
} else
temp[k++] = B[j++];
}
while (i <= j1) {
temp[k++] = B[i++];
}
while (j <= j2) {
temp[k++] = B[j++];
}
for (k = 0; k < n; k++) {
B[i1++] = temp[k];
}
}
public static void MergeSort(int[] B) {
int i1, i2, j1, j2;
int size = 1;
int n = B.length;
while (size <= n) {
i1 = 0;
while (i1 < n) {
j1 = i1 + size - 1;
if(j1= n) {
j2 = n - 1;
} else {
j2 = i2 + size - 1;
}
Merge(B, i1, j1, i2, j2);
i1 = j2 + 1;
}
else break;
}
size*=2;
}
}
public static void main(String[] args) {
MergeSort(A);
for (int i = 0; i < A.length; i++) {
System.out.printf("%d\t", A[i]);
}
}
}
书上例子:又是扑克,一张张正面朝上 平铺,两堆两堆的合
分治的典型例子 用递归 治 分成的小问题