Given an array of non-negative integers, you are initially positioned at the first index of the array.
Each element in the array represents your maximum jump length at that position.
Determine if you are able to reach the last index.
For example:
A = [2,3,1,1,4], return true.
A = [3,2,1,0,4], return false.
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贪心法,首先计算每个位置能够达到的最远的位置
然后用res表示当前位置能够走道的最远位置,每次循环的时候,直接取[i,res]之间的最大值,更新res
如果res达到最后一个元素,那么就是成功
class Solution(object):
def canJump(self, nums):
if len(nums) == 1:
return True
for i in xrange(len(nums)):
nums[i] += i
res = nums[0]
i = 1
goal = len(nums) - 1
while i <= res:
if i == res:
res = max(res,nums[i])
i += 1
else:
i,res = res,max(nums[i:res+1])
if res >= goal:
return True
return False

本文介绍了一个经典的算法问题——跳跃游戏。玩家需要判断是否能从数组的起始位置到达末尾。文章详细解释了如何使用贪心算法来解决这个问题,并提供了一个Python实现的例子。
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