题目:
从键盘分别输入年、月、日,判断这一天是当年的第几天
注:判断一年是否是闰年的标准:
1)可以被4整除,但不可被100整除
2)可以被400整除
实现:
import java.util.Scanner;
public class MyDate
{
public static void main(String[] args)
{
Scanner scanner = new Scanner(System.in);
//输入年份、月份、日期
System.out.print("请输入年份:");
int year = scanner.nextInt();
System.out.print("请输入月份:");
int month = scanner.nextInt();
System.out.print("请输入日期:");
int day = scanner.nextInt();
int sumDays = 0;
boolean leapYear;
//判断输入的年份是否为闰年
if((year % 4 == 0 && year % 100 != 0) || year % 400 == 0){
leapYear = true;
}
else{
leapYear = false;
}
//计算输入的日期为该年份的第几天
//时间从1979年1月1日开始计算
if(year < 1979 || month < 1 || month > 12 || day<1 || day > 31){
//判断输入的日期是否合法
System.out.println("你输入的日期不合法!!!");
}
else if((leapYear == true && month == 2 && day>29)||
(leapYear == false && month == 2 && day>28)){
//判断输入的日期是否合法
System.out.println("你输入的日期不合法!!!");
}
else{
switch (month){
case 12:
sumDays = 30;
case 11:
sumDays += 31;
case 10:
sumDays += 30;
case 9:
sumDays += 31;
case 8:
sumDays += 31;
case 7:
sumDays += 30;
case 6:
sumDays += 31;
case 5:
sumDays += 30;
case 4:
sumDays += 31;
case 3:
if(leapYear){
sumDays += 29;
}
else{
sumDays += 28;
}
case 2:
sumDays += 31;
case 1:
sumDays += day;
}
//输出运行结果
if(leapYear){
System.out.println(year+"年"+month+"月"+day+"日为"+year+"年的第"
+sumDays+"天,"+"该年为闰年。");
}
else{
System.out.println(year+"年"+month+"月"+day+"日为"+year+"年的第"
+sumDays+"天,"+"该年不是闰年。");
}
}
}
}