内容很简单.我之前配置cxf总是出来404我是看着demo做的啊,怎么会呢.
我就从项目中找啊找.我的项目是Spring2.5.6+Hibernate3.3.1+Struts2.1.8.1+urlrewrite3.2+cxf2.3.5
这个是我的web.xml
通常的都是这么配置的,但是你其他的写完了之后呢就会发现总是出现404错误.
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:cngrideye-config.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.util.IntrospectorCleanupListener</listener-class>
</listener>
<servlet>
<servlet-name>CXFServlet</servlet-name>
<servlet-class>org.apache.cxf.transport.servlet.CXFServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>CXFServlet</servlet-name>
<url-pattern>/services1/*</url-pattern>
</servlet-mapping>
<!-- 静态URL
要放在struts2过滤器前面.
-->
<filter>
<filter-name>UrlRewriteFilter</filter-name>
<filter-class>
org.tuckey.web.filters.urlrewrite.UrlRewriteFilter
</filter-class>
<init-param>
<param-name>logLevel</param-name>
<param-value>WARN</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>UrlRewriteFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>struts2</filter-name>
<!--
<filter-class>
org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-class>
-->
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/*</url-pattern>
<dispatcher>REQUEST</dispatcher>
<dispatcher>FORWARD</dispatcher>
<dispatcher>INCLUDE</dispatcher>
<!--
<url-pattern>*.action</url-pattern>
<url-pattern>*.jsp</url-pattern>
-->
</filter-mapping>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<login-config>
<auth-method>BASIC</auth-method>
</login-config>
</web-app>
我的cxf配置如下.
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:jaxws="http://cxf.apache.org/jaxws"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://cxf.apache.org/jaxws http://cxf.apache.org/schemas/jaxws.xsd">
<import resource="classpath:META-INF/cxf/cxf.xml" />
<import resource="classpath:META-INF/cxf/cxf-extension-soap.xml" />
<import resource="classpath:META-INF/cxf/cxf-servlet.xml" />
<jaxws:endpoint id="Hello" implementor="cn.aozer.armsweb.webservice.impl.DataImpl"
address="/HelloWorld" />
</beans>
404如下:
这时候就有多种解决方法了.
第一就是:把struts2匹配原则改一下改成*.action
第二就是:把cxf匹配改一下,改成*.ws
第三就是:吧bean里面修改改成helloword.ws
我建议用第三种.