一、equals方法。
1、当一个对象没覆盖equals方式时,默认情况下equals方法都是调用Object类的equals方法,而Object的
equals方法主要用于判断对象的内存地址引用是不是同一个地址(是不是同一个对象)。
源码如下;
2、要是类中覆盖了equals方法,必须根据具体的代码来确定equals方法的作用了,覆盖后一般都是通过对象
的内容是否相等来判断对象是否相等。
二、案例分析。
(1)、案例一:这里有学生类student。源码如下:
package org.wangkeqing;
public class Student {
private int age;
private String name;
public Student(int age, String name) {
super();
this.age = age;
this.name = name;
}
public int getAge() {
return age;
}
public String getName() {
return name;
}
public void setAge(int age) {
this.age = age;
}
public void setName(String name) {
this.name = name;
}
public static void main(String[] args) {
Student stu1 = new Student(20,"张三");
Student stu2 = new Student(20,"张三");
System.out.println("stu1 == stu2 : "+(stu1 == stu2));
System.out.println("stu1.equals(stu2) : "+stu1.equals(stu2));
}
}
运行结果:
stu1 == stu2 : false
stu1.equals(stu2) : false
案例总结:Student类没有覆盖equals方法,stu1调用equals方法实际上调用的是Object的equals方法。所以采用对象
内存地址是否相等来判断对象是否相等。因为是两个新对象所以对象的内存地址不相等,所以stu1.equals(stu2) 是false。
(2)、案例2:同样是student类,此时覆盖了equals方法,源码如下:
package org.wangkeqing;
public class Student {
private int age;
private String name;
public Student(int age, String name) {
super();
this.age = age;
this.name = name;
}
public int getAge() {
return age;
}
public String getName() {
return name;
}
public void setAge(int age) {
this.age = age;
}
public void setName(String name) {
this.name = name;
}
@Override
public boolean equals(Object obj) {
if (this == obj){
return true;
}
if (obj == null){
return false;
}
if (getClass() != obj.getClass()){
return false;
}
Student other = (Student) obj;
if (age != other.age){
return false;
}
if (name == null) {
if (other.name != null){
return false;
}
} else if (!name.equals(other.name)){
return false;
}
return true;
}
public static void main(String[] args) {
Student stu1 = new Student(20,"张三");
Student stu2 = new Student(20,"张三");
System.out.println("stu1 == stu2 : "+(stu1 == stu2));
System.out.println("stu1.equals(stu2) : "+stu1.equals(stu2));
}
}
运行如下:
stu1 == stu2 : false
stu1.equals(stu2) : true
案例总结:当覆盖了equals方法后,equals运行的结果为true,此时调用的是本身的equals方法。二、HashCode方法。
通过案例2可以知道,覆盖的equals方法已经生效,在下面的案例3中,我们覆盖student类的hashCode方法,此时先不覆盖equals方法。这里生成HashCode的方法,我们使用name和age来生成哈希码。
package org.wangkeqing;
import java.util.HashSet;
import java.util.LinkedList;
import java.util.Set;
public class Student {
private int age;
private String name;
public Student(int age, String name) {
super();
this.age = age;
this.name = name;
}
public int getAge() {
return age;
}
public String getName() {
return name;
}
public void setAge(int age) {
this.age = age;
}
public void setName(String name) {
this.name = name;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + age;
result = prime * result + ((name == null) ? 0 : name.hashCode());
return result;
}
public static void main(String[] args) {
LinkedList<Student> list = new LinkedList<Student>();
Set<Student> set = new HashSet<Student>();
Student stu1 = new Student(20,"张三");
Student stu2 = new Student(20,"张三");
System.out.println("stu1 == stu2 : "+(stu1 == stu2));
System.out.println("stu1.equals(stu2) : "+stu1.equals(stu2));
list.add(stu1);
list.add(stu2);
System.out.println("list大小:"+ list.size());
set.add(stu1);
set.add(stu2);
System.out.println("set大小:"+ set.size());
}
}
运行结果:
stu1 == stu2 : false
stu1.equals(stu2) : false
list大小:2
set大小:2
案例总结:在student中并没有覆盖equals方法只覆盖了hashCode方法,两个对象虽然hashCode一样,但在将stu1和stu2放入set集合时由于equals方法比较的两个对象是false,所以就没有在比较两个对象的hashcode值。
案例4:同时覆盖equals方法和HashCode方法。源码如下:
package org.wangkeqing;
import java.util.HashSet;
import java.util.LinkedList;
import java.util.Set;
public class Student {
private int age;
private String name;
public Student(int age, String name) {
super();
this.age = age;
this.name = name;
}
public int getAge() {
return age;
}
public String getName() {
return name;
}
public void setAge(int age) {
this.age = age;
}
public void setName(String name) {
this.name = name;
}
@Override
public boolean equals(Object obj) {
if (this == obj){
return true;
}
if (obj == null){
return false;
}
if (getClass() != obj.getClass()){
return false;
}
Student other = (Student) obj;
if (age != other.age){
return false;
}
if (name == null) {
if (other.name != null){
return false;
}
} else if (!name.equals(other.name)){
return false;
}
return true;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + age;
result = prime * result + ((name == null) ? 0 : name.hashCode());
return result;
}
public static void main(String[] args) {
LinkedList<Student> list = new LinkedList<Student>();
Set<Student> set = new HashSet<Student>();
Student stu1 = new Student(20,"张三");
Student stu2 = new Student(20,"张三");
System.out.println("stu1 == stu2 : "+(stu1 == stu2));
System.out.println("stu1.equals(stu2) : "+stu1.equals(stu2));
list.add(stu1);
list.add(stu2);
System.out.println("list大小:"+ list.size());
set.add(stu1);
set.add(stu2);
System.out.println("set大小:"+ set.size());
}
}
运行结果:
stu1 == stu2 : false
stu1.equals(stu2) : true
list大小:2
set大小:1
案例4总结:从运行结果可以看出,此时equals方法结果为true,两个对象内容相等。但是==比较的是两个对象的引用地址是否相等。显然,他们不是同一个对象。在把对象存入list和set中,由于HashCode相等,故而在对象存入set中,就是同一个值。
案例5:同时覆盖equals方法和HashCode方法,但是生成不同的HashCode,源代码如下:
package org.wangkeqing;
import java.util.HashSet;
import java.util.LinkedList;
import java.util.Set;
public class Student {
private int age;
private String name;
public Student(int age, String name) {
super();
this.age = age;
this.name = name;
}
public int getAge() {
return age;
}
public String getName() {
return name;
}
public void setAge(int age) {
this.age = age;
}
public void setName(String name) {
this.name = name;
}
@Override
public boolean equals(Object obj) {
if (this == obj){
return true;
}
if (obj == null){
return false;
}
if (getClass() != obj.getClass()){
return false;
}
Student other = (Student) obj;
if (age != other.age){
return false;
}
if (name == null) {
if (other.name != null){
return false;
}
} else if (!name.equals(other.name)){
return false;
}
return true;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + age;
result = prime * result + ((name == null) ? 0 : name.hashCode());
System.out.println("hashCode : "+ result);
return result;
}
public static void main(String[] args) {
LinkedList<Student> list = new LinkedList<Student>();
Set<Student> set = new HashSet<Student>();
Student stu1 = new Student(20,"张三");
Student stu2 = new Student(20,"张三");
System.out.println("stu1 == stu2 : "+(stu1 == stu2));
System.out.println("stu1.equals(stu2) : "+stu1.equals(stu2));
list.add(stu1);
list.add(stu2);
System.out.println("list大小:"+ list.size());
set.add(stu1);
set.add(stu2);
System.out.println("set大小:"+ set.size());
System.out.println("-------------------------------------------------------------");
stu1.setAge(30);
System.out.println("删除 stu1 : "+set.remove(stu1));
System.out.println("set size:"+ set.size());
}
}
运行结果如下:
stu1 == stu2 : false
stu1.equals(stu2) : true
list大小:2
hashCode : 776470
hashCode : 776470
set大小:1
-------------------------------------------------------------
hashCode : 776780
删除 stu1 : false
set size:1
案例5总结:当我们将某个对象存到set,Map等数据结构中时,如果对象的属性参与了hashcode的计算,那么以后就不能修改该对象参与hashcode计算的那些属性了,否则会引起意向不到的错误的。