soso130731的博客

拨测程序： ''' import sys import os curPath = os.path.abspath(os.path.dirname(__file__)) print(curPath) rootPath = os.path.split(curPath)[0] print(rootPath) sys.path.append(rootPath) ''' #index_page,myInfo_page,,relative_page #from src.common import gesture_m

结合单元测试框架unittest，直接贴代码： # -*- coding: utf-8 -*- import unittest from selenium import webdriver #from object.DRIVER import getDriver import time,queue import login_page,BasePage class UntitledTestCase(unittest.TestCase): def setUp(self): #Opt.

play： import pyaudio import wave import time from tqdm import tqdm def play_audio(wave_path): ''' while True: print('play') time.sleep(1) ''' time.sleep(0.1) CHUNK = 1024 f = wa...

#!/usr/bin/python import time, threading import random import struct import gevent import signal import os from gevent import socket import psutil import sys thread_num = 2 #open thread num is_exit...

用python为服务写了个压力测试。很简单，多线程向服务器发请求。但写完之后发现如果中途想停下来，按Ctrl+C达不到效果，自然想到要用信号处理函数捕捉信号，使线程都停下来，问题解决的方法请往下看： 复制代码代码如下: #!/bin/env python # -*- coding: utf-8 -*- #filename: peartest.py import threading, ...

#coding=utf-8 import psutil import sys import time import os def listen(PID): f = open('listen_server.txt','w') i = 1 while i == 1 : p1 = psutil.Process(PID) cpu1 = p1.cpu...

要获取到目标元素的text的值，需要定义一个目标元素element，然后通过element.text方法得到字符串 error_mes = driver.find_element_by_xpath("//*[@id='TANGRAM__PSP_10__error']").text time.sleep(5) print (error_mes) try: assert error_me...