CodeForces-570A Elections

本文详细阐述了如何通过编程实现选举算法,包括输入处理、投票计数和输出获胜者的过程。重点介绍了如何从输入中读取候选人数和投票数据,通过算法计算得出票数最高的候选人,并输出其序号作为最终结果。

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#include <iostream>
#include <cstdio>
#include <algorithm>
#include <cstring>

using namespace std;

const int maxn = 100 + 5;
int vote[maxn][maxn];
int candidate[maxn];
int n, m;

int main()
{
    while(~scanf("%d %d", & n, & m))
    {
        memset(candidate, 0, sizeof(candidate));
        for(int i = 0; i < m; i ++)
        {
            int Max = 0;
            for(int j = 0; j < n; j ++)
            {
                scanf("%d", & vote[i][j]);
                if(vote[i][j] > vote[i][Max])
                    Max = j;
            }
            candidate[Max] ++;
        }
        int win = 0;
        for(int i = 0; i < n; i ++)
            if(candidate[i] > candidate[win])
                win = i;
        printf("%d\n", win + 1);
    }
    return 0;
}

题意:选举。输入n(表示候选人数)输入m(表示参与选举的城市)。接下来m行表示每个城市对n个候选人的投票情况。票数最高的候选人算当行城市所推荐的人(即票数+1)(如果最大票数出现相同情况 取下标最小的候选人)。输出最后获胜的候选人序号。

题解:水题。

### Codeforces Problem 976C Solution in Python For solving problem 976C on Codeforces using Python, efficiency becomes a critical factor due to strict time limits aimed at distinguishing between efficient and less efficient solutions[^1]. Given these constraints, it is advisable to focus on optimizing algorithms and choosing appropriate data structures. The provided code snippet offers insight into handling string manipulation problems efficiently by customizing comparison logic for sorting elements based on specific criteria[^2]. However, for addressing problem 976C specifically, which involves determining the winner ('A' or 'B') based on frequency counts within given inputs, one can adapt similar principles of optimization but tailored towards counting occurrences directly as shown below: ```python from collections import Counter def determine_winner(): for _ in range(int(input())): count_map = Counter(input().strip()) result = "A" if count_map['A'] > count_map['B'] else "B" print(result) determine_winner() ``` This approach leverages `Counter` from Python’s built-in `collections` module to quickly tally up instances of 'A' versus 'B'. By iterating over multiple test cases through a loop defined by user input, this method ensures that comparisons are made accurately while maintaining performance standards required under tight computational resources[^3]. To further enhance execution speed when working with Python, consider submitting codes via platforms like PyPy instead of traditional interpreters whenever possible since they offer better runtime efficiencies especially important during competitive programming contests where milliseconds matter significantly.
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