PHAS0038: Electromagnetic Theory PST Example Problems 2SQL

Java Python PHAS0038: Electromagnetic Theory

PST Example Problems 2

These problems will be demonstrated during the Problem Solving sessions in Week 5. This document (without solutions) will be handed out as hardcopy during the PS sessions. Solutions will be typeset and added to and online version of this document after those sessions have taken place.

1. To be demonstrated in class: Consider a region in which the magnetic field B varies in space as a function of position r, but does not vary with time t. Now consider a closed curve Γ, which moves through this region, keeping its fixed shape. Each point on the curve thus moves with the same velocity vo. Show that the rate of change of magnetic flux through any surface bounded by Γ is given by the line integral 

2. To be attempted in class: Generalise the result from the previous question to consider a rectangular loop initially at rest in the xy plane, with its centre at the origin. The loop has edges of length b parallel to the x axis and length a parallel to the y axis. The loop is mounted on an axis of rotation which runs parallel to the y axis and passes through its centre. The loop is embedded in a uniform. magnetic field B = B0zˆ which is parallel to the z axis.

At time zero, the loop is set into rotational motion with angular velocity !0 about the y axis. What is the magnitude of the EMF induced around the loop when motion com-mences? The subsequent angular velocity of the loop is described by a function of time  (for an appropriately defined angle φ). If the loop has a fixed resistance R, can you derive an expression for the torque exerted on the loop at time t?

3. Consider a cylindrical bar magnet (ferromagnet), which has a large permanent magnetiza-tion M in its interior (M is parallel to the cylinder axis of symmetry). M is approximately uniform. and large such that, in the interior of the magne PHAS0038: Electromagnetic Theory PST Example Problems 2SQL t, B ≈ µ0M.

The magnet starts to move along the x axis (i.e. its cylindrical axis of symmetry remains on the Cartesian x axis). It starts from a position with its centre at x = L (L > 0) and moves with uniform. velocity in the negative x direction. At time tC, it has passed halfway through a conducting loop which has a radius a just large enough to allow it through. It then passes through the loop and proceeds to the position x = −L. Assuming L >> a, draw a graph of how you would expect the magnetic flux through the loop to change with time, due only to the passage of the magnet, from t = 0 to t = 2tC. Draw a corresponding graph of the magnitude of the EMF induced around the loop as a function of time.

4. A single circular conducting loop of radius d<a is placed inside a long solenoid of cylindrical radius a. The plane of the loop is initially perpendicular to the z (symmetry) axis of the solenoid. The solenoid carries n turns of wire per unit length through which a steady current I is flowing. It is long enough that the ‘infinite length’ approximation for its interior magnetic field is valid.

The loop then starts rotating about one of its diameters, so that the smallest angle between the z axis and the plane of the loop is ξ = π/2 − Ωt, where Ω is a constant, and t is time. Using this information, derive expressions for:

(i) The time-dependent magnitude of the mutual inductance between the solenoid and the loop (assuming that the solenoid is the only significant source of magnetic flux through the loop). The mutual inductance M can be defined by the equality Φ = MI, where Φ is the magnetic flux through the loop. (For revision / introduction to mutual inductance and self inductance, see the additional notes on Moodle related to ‘Notes and Solved Problems on Inductance’).

(ii) The time-dependent magnitude of the electromotive force (EMF) induced in the ro-tating loop         

基于模拟退火的计算器 在线运行 访问run.bcjh.xyz。 先展示下效果 https://pan.quark.cn/s/cc95c98c3760 参见此仓库。 使用方法(本地安装包) 前往Releases · hjenryin/BCJH-Metropolis下载最新 ,解压后输入游戏内校验码即可使用。 配置厨具 已在2.0.0弃用。 直接使用白菜菊花代码,保留高级厨具,新手池厨具可变。 更改迭代次数 如有需要,可以更改 中39行的数字来设置迭代次数。 本地编译 如果在windows平台,需要使用MSBuild编译,并将 改为ANSI编码。 如有条件,强烈建议这种本地运行(运行可加速、可多次重复)。 在 下运行 ,是游戏中的白菜菊花校验码。 编译、运行: - 在根目录新建 文件夹并 至build - - 使用 (linux) 或 (windows) 运行。 最后在命令行就可以得到输出结果了! (注意顺序)(得到厨师-技法,表示对应新手池厨具) 注:linux下不支持多任务选择 云端编译已在2.0.0弃用。 局限性 已知的问题: - 无法得到最优解! 只能得到一个比较好的解,有助于开阔思路。 - 无法选择菜品数量(默认拉满)。 可能有一定门槛。 (这可能有助于防止这类辅助工具的滥用导致分数膨胀? )(你问我为什么不用其他语言写? python一个晚上就写好了,结果因为有涉及json读写很多类型没法推断,jit用不了,算这个太慢了,所以就用c++写了) 工作原理 采用两层模拟退火来最大化总能量。 第一层为三个厨师,其能量用第二层模拟退火来估计。 也就是说,这套方法理论上也能算厨神(只要能够在非常快的时间内,算出一个厨神面板的得分),但是加上厨神的食材限制工作量有点大……以后再说吧。 (...
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