Given a Weather
table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.
+---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+------------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +---------+------------+------------------+For example, return the following Ids for the above Weather table:
+----+ | Id | +----+ | 2 | | 4 | +----+
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MySQL:
# Write your MySQL query statement below
select
a.Id
from
Weather a,
Weather b
where
datediff(a.Date, b.Date) = 1
and a.Temperature > b.Temperature
;