版本: 5.6.16
SELECT uid, aid FROM `a` WHERE uid = 2226894 GROUP BY uid;
SELECT id, uid, aid FROM `a` WHERE uid = 2226894;
结论: group by 查询时 模棱两可的数据将会展示第一个
注意: 5.7.26 这个版本是不支持第一条sql
版本: 5.6.16
SELECT uid, aid FROM `a` WHERE uid = 2226894 GROUP BY uid;
SELECT id, uid, aid FROM `a` WHERE uid = 2226894;
结论: group by 查询时 模棱两可的数据将会展示第一个
注意: 5.7.26 这个版本是不支持第一条sql