//1_2_1: Doubles 求2倍的个数 POJ1552 ZOJ1760
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
int main()
{
int i,j,n,cnt,a[20];
scanf("%d",&a[0]);
while(a[0] != -1)
{
n = 1;
while(scanf("%d",&a[n]),a[n] != 0) n++;
cnt = 0;
for(i = 0;i < n;i ++)
for(j = i + 1;j < n;j ++)
if(a[i] == a[j] * 2 || a[j] == a[i] * 2)
cnt++;
printf("%d\n",cnt);
scanf("%d",&a[0]);
}
return 0;
}
/*测试结果:通过POJ1552 ZOJ1760检测
1 4 3 2 9 7 18 22 0
3
2 4 8 10 0
2
7 5 11 13 1 3 0
0
-1
请按任意键继续. . .
*/
POJ1552 ZOJ1760 Doubles
最新推荐文章于 2018-11-12 23:17:00 发布