ACM——1029

Ignatius and the Princess IV

Problem Description

"OK, you are not too bad, em... But you can never pass the next test." feng5166 says.

"I will tell you an odd number N, and then N integers. There will be a special integer among them, you have to tell me which integer is the special one after I tell you all the integers." feng5166 says.

"But what is the characteristic of the special integer?" Ignatius asks.

"The integer will appear at least (N+1)/2 times. If you can't find the right integer, I will kill the Princess, and you will be my dinner, too. Hahahaha....." feng5166 says.

Can you find the special integer for Ignatius?

Input

The input contains several test cases. Each test case contains two lines. The first line consists of an odd integer N(1<=N<=999999) which indicate the number of the integers feng5166 will tell our hero. The second line contains the N integers. The input is terminated by the end of file.

 

Output

For each test case, you have to output only one line which contains the special number you have found.

 

Sample Input

5
1 3 2 3 3
11
1 1 1 1 1 5 5 5 5 5 5
7
1 1 1 1 1 1 1

 

Sample Output

3
5
1

题目分析：因为必定存在这个数。所以我们可以将所有数排序，这时我们可以发现当有五个数时 为第二个数 当有七个数时 为第三个数（从0开始数）即只要找到排在中间的那个数就可以了

代码如下： 

<pre name="code" class="cpp"># include <stdio.h>
# include <algorithm>
using namespace std;

int number[999999];

int main()
{
	int n, i;
	while(scanf("%d", &n) != EOF)
	{
		for(i = 0; i < n; i++)
		{
			scanf("%d", &number[i]);
		}
		sort(number, number + n);
		i = (n + 1) / 2 - 1;
		printf("%d\n", number[i]);
	}

	return 0;
}