/**
* 获取父视图的控制器
*
* @return 父视图的控制器
*/
- (UIViewController *)viewController
{
for (UIView* next = [self superview]; next; next = next.superview) {
UIResponder *nextResponder = [next nextResponder];
if ([nextResponder isKindOfClass:[UIViewController class]]) {
return (UIViewController *)nextResponder;
}
}
return nil;
* 获取父视图的控制器
*
* @return 父视图的控制器
*/
- (UIViewController *)viewController
{
for (UIView* next = [self superview]; next; next = next.superview) {
UIResponder *nextResponder = [next nextResponder];
if ([nextResponder isKindOfClass:[UIViewController class]]) {
return (UIViewController *)nextResponder;
}
}
return nil;
}
//跳转
[[self
viewController].navigationController
pushViewController:platDetailVC
animated:YES];
本文介绍了一个Objective-C方法,用于从当前视图中获取其父视图的控制器,并展示了如何利用该控制器进行页面跳转。通过遍历视图层级结构找到对应的响应者,进而判断其是否为UIViewController实例。
422

被折叠的 条评论
为什么被折叠?



