10进制转2，8，16进制_10进制转2,8,16进制-优快云博客

本文详细介绍了将十进制数转换为十六进制、二进制和八进制的方法，并通过示例代码展示了具体实现过程。

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//十进制转十六进制

public static string to10Chang16(int d)
{

string x = "";

if (d < 16)
{

x = chang(d);

}

else
{

int c;

int s = 0;

int n = d;

int temp = d;

while (n >= 16)
{

s++;

n = n / 16;

}

string[] m = new string[s];

int i = 0;

do
{

c = d / 16;

m[i++] = chang(d % 16);//判断是否大于10，如果大于10，则转换为A~F的格式

d = c;

} while (c >= 16);

x = chang(d);

for (int j = m.Length - 1; j >= 0; j--)
{

x += m[j];

}

return x;

}

//判断是否为10~15之间的数，如果是则进行转换

public static string chang(int d)
{

string x = "";

switch (d)
{

case 10:

x = "A";

break;

case 11:

x = "B";

break;

case 12:

x = "C";

break;

case 13:

x = "D";

break;

case 14:

x = "E";

break;

case 15:

x = "F";

break;

default:

x = d.ToString();

break;

}

return x;
}

    //十进制转二制
    public static string to10Chang2(int d)
    {
        string b = "";
        //判断该数如果小于2，则直接输出
        if (d < 2)
        {
            b = d.ToString();
        }
        else
        {
            int c;
            int s = 0;
            int n = d;
            while (n >= 2)
            {
                s++;
                n = n / 2;
            }
            int[] m = new int[s];
            int i = 0;
            do
            {
                c = d / 2;
                m[i++] = d % 2;
                d = c;
            } while (c >= 2);
            b = d.ToString();
            for (int j = m.Length - 1; j >= 0; j--)
            {
                b += m[j].ToString();
            }
        }
        return b;
    }

    //十进制转八进制
    public static string to10Chang8(int d)
    {
        string o = "";
        if (d < 8)
        {
            o = d.ToString();
        }
        else
        {
            int c;

            int s = 0;
            int n = d;
            int temp = d;
            while (n >= 8)
            {
                s++;
                n = n / 8;
            }
            int[] m = new int[s];
            int i = 0;
            do
            {
                c = d / 8;
                m[i++] = d % 8;
                d = c;
            } while (c >= 8);
            o = d.ToString();
            for (int j = m.Length - 1; j >= 0; j--)
            {
                o += m[j];
            }
        }
        return o;
    }