1065. A+B and C (64bit)

1065. A+B and C (64bit) (20)

时间限制

100 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

HOU, Qiming

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

#include<iostream>

using namespace std;

int main()
{
	int n;
	cin>>n;
	long long a,b,c,s;
	bool f;
	for(int i=1;i<=n;i++)
	{
		cin>>a>>b>>c;
		s=a+b;
		if(a>0&&b>0&&s<=0)
			f=true;
		else if(a<0&&b<0&&s>=0)
			f=false;
		else
			f=(s>c);
		if(f)
			cout<<"Case #"<<i<<": "<<"true"<<endl;
		else
			cout<<"Case #"<<i<<": "<<"false"<<endl;
	}
	return 0;
}