这道题用两根指针,向中间逼近。
一定要注意的是corner case时的下标处理。
/**
*@param nums: The integer array you should partition
*@param k: As description
*return: The index after partition
*/
public int partitionArray(int[] nums, int k) {
//write your code here
if ((nums == null || nums.length == 0) || (nums.length == 1 && nums[0] > k)) {
return 0;
}
if (nums.length == 1 && nums[0] > k) {
return 1;
}
int left = 0, right = nums.length - 1;
int index = 0;
while (left < right) {
if (nums[left] < k && nums[right] >= k) {
left++;
right--;
index++;
} else if (nums[left] >= k && nums[right] >= k) {
right--;
} else if (nums[left] < k && nums[right] < k) {
left++;
index++;
} else {
int temp = nums[left];
nums[left] = nums[right];
nums[right] = temp;
left++;
right--;
index++;
}
}
if (left == nums.length - 1) {
//1 return index++;
return ++index;
} else {
//return index;
if (nums[left] < k) {
return ++index;
} else
return index;
}
//return index;
}